| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.17 |
| Score | 0% | 63% |
What is \( \frac{4}{5} \) x \( \frac{3}{8} \)?
| \(\frac{1}{24}\) | |
| 2\(\frac{2}{5}\) | |
| \(\frac{3}{10}\) | |
| \(\frac{16}{63}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{4}{5} \) x \( \frac{3}{8} \) = \( \frac{4 x 3}{5 x 8} \) = \( \frac{12}{40} \) = \(\frac{3}{10}\)
The __________ is the smallest positive integer that is a multiple of two or more integers.
least common factor |
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greatest common factor |
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least common multiple |
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absolute value |
The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.
A tiger in a zoo has consumed 40 pounds of food in 8 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 60 pounds?
| 4 | |
| 6 | |
| 11 | |
| 5 |
If the tiger has consumed 40 pounds of food in 8 days that's \( \frac{40}{8} \) = 5 pounds of food per day. The tiger needs to consume 60 - 40 = 20 more pounds of food to reach 60 pounds total. At 5 pounds of food per day that's \( \frac{20}{5} \) = 4 more days.
Simplify \( \frac{32}{64} \).
| \( \frac{2}{7} \) | |
| \( \frac{8}{11} \) | |
| \( \frac{6}{13} \) | |
| \( \frac{1}{2} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 32 are [1, 2, 4, 8, 16, 32] and the factors of 64 are [1, 2, 4, 8, 16, 32, 64]. They share 6 factors [1, 2, 4, 8, 16, 32] making 32 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{32}{64} \) = \( \frac{\frac{32}{32}}{\frac{64}{32}} \) = \( \frac{1}{2} \)
If all of a roofing company's 10 workers are required to staff 5 roofing crews, how many workers need to be added during the busy season in order to send 9 complete crews out on jobs?
| 14 | |
| 10 | |
| 8 | |
| 16 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 10 workers at the company now and that's enough to staff 5 crews so there are \( \frac{10}{5} \) = 2 workers on a crew. 9 crews are needed for the busy season which, at 2 workers per crew, means that the roofing company will need 9 x 2 = 18 total workers to staff the crews during the busy season. The company already employs 10 workers so they need to add 18 - 10 = 8 new staff for the busy season.