| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.41 |
| Score | 0% | 68% |
Charlie loaned Damon $1,400 at an annual interest rate of 3%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $18 | |
| $6 | |
| $42 | |
| $10 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,400
i = 0.03 x $1,400
i = $42
17 members of a bridal party need transported to a wedding reception but there are only 4 3-passenger taxis available to take them. How many will need to find other transportation?
| 9 | |
| 5 | |
| 4 | |
| 1 |
There are 4 3-passenger taxis available so that's 4 x 3 = 12 total seats. There are 17 people needing transportation leaving 17 - 12 = 5 who will have to find other transportation.
If all of a roofing company's 6 workers are required to staff 3 roofing crews, how many workers need to be added during the busy season in order to send 6 complete crews out on jobs?
| 6 | |
| 17 | |
| 10 | |
| 19 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 6 workers at the company now and that's enough to staff 3 crews so there are \( \frac{6}{3} \) = 2 workers on a crew. 6 crews are needed for the busy season which, at 2 workers per crew, means that the roofing company will need 6 x 2 = 12 total workers to staff the crews during the busy season. The company already employs 6 workers so they need to add 12 - 6 = 6 new staff for the busy season.
The __________ is the greatest factor that divides two integers.
greatest common multiple |
|
least common multiple |
|
absolute value |
|
greatest common factor |
The greatest common factor (GCF) is the greatest factor that divides two integers.
What is \( \frac{27\sqrt{15}}{9\sqrt{5}} \)?
| \(\frac{1}{3}\) \( \sqrt{3} \) | |
| 3 \( \sqrt{\frac{1}{3}} \) | |
| \(\frac{1}{3}\) \( \sqrt{\frac{1}{3}} \) | |
| 3 \( \sqrt{3} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{27\sqrt{15}}{9\sqrt{5}} \)
\( \frac{27}{9} \) \( \sqrt{\frac{15}{5}} \)
3 \( \sqrt{3} \)