| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.19 |
| Score | 0% | 64% |
What is the greatest common factor of 52 and 76?
| 33 | |
| 7 | |
| 4 | |
| 3 |
The factors of 52 are [1, 2, 4, 13, 26, 52] and the factors of 76 are [1, 2, 4, 19, 38, 76]. They share 3 factors [1, 2, 4] making 4 the greatest factor 52 and 76 have in common.
Solve 5 + (3 + 2) ÷ 5 x 3 - 42
| \(\frac{5}{7}\) | |
| \(\frac{5}{6}\) | |
| 4 | |
| -8 |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
5 + (3 + 2) ÷ 5 x 3 - 42
P: 5 + (5) ÷ 5 x 3 - 42
E: 5 + 5 ÷ 5 x 3 - 16
MD: 5 + \( \frac{5}{5} \) x 3 - 16
MD: 5 + \( \frac{15}{5} \) - 16
AS: \( \frac{25}{5} \) + \( \frac{15}{5} \) - 16
AS: \( \frac{40}{5} \) - 16
AS: \( \frac{40 - 80}{5} \)
\( \frac{-40}{5} \)
-8
What is the distance in miles of a trip that takes 5 hours at an average speed of 65 miles per hour?
| 100 miles | |
| 325 miles | |
| 70 miles | |
| 120 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 65mph \times 5h \)
325 miles
A bread recipe calls for 3\(\frac{5}{8}\) cups of flour. If you only have \(\frac{5}{8}\) cup, how much more flour is needed?
| 3 cups | |
| 1\(\frac{3}{4}\) cups | |
| 1\(\frac{1}{2}\) cups | |
| 3\(\frac{1}{8}\) cups |
The amount of flour you need is (3\(\frac{5}{8}\) - \(\frac{5}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{29}{8} \) - \( \frac{5}{8} \)) cups
\( \frac{24}{8} \) cups
3 cups
Cooks are needed to prepare for a large party. Each cook can bake either 5 large cakes or 17 small cakes per hour. The kitchen is available for 4 hours and 39 large cakes and 340 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 9 | |
| 7 | |
| 13 | |
| 15 |
If a single cook can bake 5 large cakes per hour and the kitchen is available for 4 hours, a single cook can bake 5 x 4 = 20 large cakes during that time. 39 large cakes are needed for the party so \( \frac{39}{20} \) = 1\(\frac{19}{20}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 17 small cakes per hour and the kitchen is available for 4 hours, a single cook can bake 17 x 4 = 68 small cakes during that time. 340 small cakes are needed for the party so \( \frac{340}{68} \) = 5 cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 2 + 5 = 7 cooks.