ASVAB Arithmetic Reasoning Practice Test 864600 Results

Your Results Global Average
Questions 5 5
Correct 0 3.04
Score 0% 61%

Review

1

Solve for \( \frac{5!}{2!} \)

67% Answer Correctly
6
60
840
\( \frac{1}{60480} \)

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{5!}{2!} \)
\( \frac{5 \times 4 \times 3 \times 2 \times 1}{2 \times 1} \)
\( \frac{5 \times 4 \times 3}{1} \)
\( 5 \times 4 \times 3 \)
60


2

Jennifer scored 84% on her final exam. If each question was worth 3 points and there were 270 possible points on the exam, how many questions did Jennifer answer correctly?

57% Answer Correctly
75
73
90
76

Solution

Jennifer scored 84% on the test meaning she earned 84% of the possible points on the test. There were 270 possible points on the test so she earned 270 x 0.84 = 228 points. Each question is worth 3 points so she got \( \frac{228}{3} \) = 76 questions right.


3

Solve 4 + (3 + 4) ÷ 3 x 3 - 52

53% Answer Correctly
\(\frac{2}{3}\)
2\(\frac{1}{2}\)
1
-14

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

4 + (3 + 4) ÷ 3 x 3 - 52
P: 4 + (7) ÷ 3 x 3 - 52
E: 4 + 7 ÷ 3 x 3 - 25
MD: 4 + \( \frac{7}{3} \) x 3 - 25
MD: 4 + \( \frac{21}{3} \) - 25
AS: \( \frac{12}{3} \) + \( \frac{21}{3} \) - 25
AS: \( \frac{33}{3} \) - 25
AS: \( \frac{33 - 75}{3} \)
\( \frac{-42}{3} \)
-14


4

What is the next number in this sequence: 1, 5, 13, 25, 41, __________ ?

69% Answer Correctly
61
52
56
57

Solution

The equation for this sequence is:

an = an-1 + 4(n - 1)

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 4(6 - 1)
a6 = 41 + 4(5)
a6 = 61


5

If there were a total of 350 raffle tickets sold and you bought 24 tickets, what's the probability that you'll win the raffle?

60% Answer Correctly
7%
9%
2%
4%

Solution

You have 24 out of the total of 350 raffle tickets sold so you have a (\( \frac{24}{350} \)) x 100 = \( \frac{24 \times 100}{350} \) = \( \frac{2400}{350} \) = 7% chance to win the raffle.