ASVAB Arithmetic Reasoning Practice Test 865391 Results

Your Results Global Average
Questions 5 5
Correct 0 3.20
Score 0% 64%

Review

1

The __________ is the smallest positive integer that is a multiple of two or more integers.

56% Answer Correctly

greatest common factor

least common factor

absolute value

least common multiple


Solution

The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.


2

Solve for \( \frac{2!}{3!} \)

67% Answer Correctly
\( \frac{1}{210} \)
\( \frac{1}{3024} \)
\( \frac{1}{3} \)
\( \frac{1}{336} \)

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{2!}{3!} \)
\( \frac{2 \times 1}{3 \times 2 \times 1} \)
\( \frac{1}{3} \)
\( \frac{1}{3} \)


3

Simplify \( \frac{36}{76} \).

77% Answer Correctly
\( \frac{1}{2} \)
\( \frac{9}{19} \)
\( \frac{7}{16} \)
\( \frac{5}{16} \)

Solution

To simplify this fraction, first find the greatest common factor between them. The factors of 36 are [1, 2, 3, 4, 6, 9, 12, 18, 36] and the factors of 76 are [1, 2, 4, 19, 38, 76]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).

Next, divide both numerator and denominator by the GCF:

\( \frac{36}{76} \) = \( \frac{\frac{36}{4}}{\frac{76}{4}} \) = \( \frac{9}{19} \)


4

Roger loaned Alex $300 at an annual interest rate of 3%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$18
$9
$27
$16

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $300
i = 0.03 x $300
i = $9


5

If a rectangle is twice as long as it is wide and has a perimeter of 42 meters, what is the area of the rectangle?

47% Answer Correctly
2 m2
98 m2
32 m2
162 m2

Solution

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 42 meters so the equation becomes: 2w + 2h = 42.

Putting these two equations together and solving for width (w):

2w + 2h = 42
w + h = \( \frac{42}{2} \)
w + h = 21
w = 21 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 21 - 2w
3w = 21
w = \( \frac{21}{3} \)
w = 7

Since h = 2w that makes h = (2 x 7) = 14 and the area = h x w = 7 x 14 = 98 m2