ASVAB Arithmetic Reasoning Practice Test 865950 Results

Your Results Global Average
Questions 5 5
Correct 0 3.22
Score 0% 64%

Review

1

A triathlon course includes a 200m swim, a 20.2km bike ride, and a 11.6km run. What is the total length of the race course?

69% Answer Correctly
59.3km
53.4km
43.6km
32km

Solution

To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 200 meters to kilometers, divide the distance by 1000 to get 0.2km then add the remaining distances:

total distance = swim + bike + run
total distance = 0.2km + 20.2km + 11.6km
total distance = 32km


2

Which of these numbers is a factor of 48?

68% Answer Correctly
30
52
1
8

Solution

The factors of a number are all positive integers that divide evenly into the number. The factors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24, 48.


3

4! = ?

85% Answer Correctly

4 x 3 x 2 x 1

3 x 2 x 1

4 x 3

5 x 4 x 3 x 2 x 1


Solution

A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.


4

What is 4\( \sqrt{2} \) x 4\( \sqrt{9} \)?

41% Answer Correctly
8\( \sqrt{2} \)
48\( \sqrt{2} \)
16\( \sqrt{11} \)
16\( \sqrt{9} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

4\( \sqrt{2} \) x 4\( \sqrt{9} \)
(4 x 4)\( \sqrt{2 \times 9} \)
16\( \sqrt{18} \)

Now we need to simplify the radical:

16\( \sqrt{18} \)
16\( \sqrt{2 \times 9} \)
16\( \sqrt{2 \times 3^2} \)
(16)(3)\( \sqrt{2} \)
48\( \sqrt{2} \)


5

What is \( \frac{8}{4} \) + \( \frac{9}{10} \)?

59% Answer Correctly
1 \( \frac{6}{20} \)
2 \( \frac{3}{7} \)
2\(\frac{9}{10}\)
1 \( \frac{7}{10} \)

Solution

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [20, 40, 60, 80] making 20 the smallest multiple 4 and 10 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{8 x 5}{4 x 5} \) + \( \frac{9 x 2}{10 x 2} \)

\( \frac{40}{20} \) + \( \frac{18}{20} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{40 + 18}{20} \) = \( \frac{58}{20} \) = 2\(\frac{9}{10}\)