ASVAB Arithmetic Reasoning Practice Test 866456 Results

Your Results Global Average
Questions 5 5
Correct 0 3.44
Score 0% 69%

Review

1

If \( \left|x + 7\right| \) - 2 = -2, which of these is a possible value for x?

62% Answer Correctly
-1
-7
5
8

Solution

First, solve for \( \left|x + 7\right| \):

\( \left|x + 7\right| \) - 2 = -2
\( \left|x + 7\right| \) = -2 + 2
\( \left|x + 7\right| \) = 0

The value inside the absolute value brackets can be either positive or negative so (x + 7) must equal + 0 or -0 for \( \left|x + 7\right| \) to equal 0:

x + 7 = 0
x = 0 - 7
x = -7
x + 7 = 0
x = 0 - 7
x = -7

So, x = -7 or x = -7.


2

Which of the following is not an integer?

77% Answer Correctly

-1

\({1 \over 2}\)

1

0


Solution

An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.


3

The __________ is the greatest factor that divides two integers.

67% Answer Correctly

greatest common factor

least common multiple

greatest common multiple

absolute value


Solution

The greatest common factor (GCF) is the greatest factor that divides two integers.


4

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

56% Answer Correctly

commutative property for multiplication

distributive property for division

distributive property for multiplication

commutative property for division


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).


5

How many 12-passenger vans will it take to drive all 51 members of the football team to an away game?

81% Answer Correctly
12 vans
4 vans
5 vans
6 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{51}{12} \) = 4\(\frac{1}{4}\)

So, it will take 4 full vans and one partially full van to transport the entire team making a total of 5 vans.