ASVAB Arithmetic Reasoning Practice Test 869764 Results

Your Results Global Average
Questions 5 5
Correct 0 2.70
Score 0% 54%

Review

1

The total water usage for a city is 20,000 gallons each day. Of that total, 30% is for personal use and 48% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?

58% Answer Correctly
4,400
3,600
4,500
2,400

Solution

48% of the water consumption is industrial use and 30% is personal use so (48% - 30%) = 18% more water is used for industrial purposes. 20,000 gallons are consumed daily so industry consumes \( \frac{18}{100} \) x 20,000 gallons = 3,600 gallons.


2

Christine scored 88% on her final exam. If each question was worth 2 points and there were 120 possible points on the exam, how many questions did Christine answer correctly?

57% Answer Correctly
39
65
44
53

Solution

Christine scored 88% on the test meaning she earned 88% of the possible points on the test. There were 120 possible points on the test so she earned 120 x 0.88 = 106 points. Each question is worth 2 points so she got \( \frac{106}{2} \) = 53 questions right.


3

Which of the following statements about exponents is false?

47% Answer Correctly

b1 = b

all of these are false

b0 = 1

b1 = 1


Solution

A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).


4

What is the least common multiple of 6 and 8?

72% Answer Correctly
18
24
32
13

Solution

The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80]. The first few multiples they share are [24, 48, 72, 96] making 24 the smallest multiple 6 and 8 have in common.


5

What is \( 6 \)\( \sqrt{28} \) + \( 8 \)\( \sqrt{7} \)

35% Answer Correctly
14\( \sqrt{7} \)
48\( \sqrt{7} \)
14\( \sqrt{28} \)
20\( \sqrt{7} \)

Solution

To add these radicals together their radicands must be the same:

6\( \sqrt{28} \) + 8\( \sqrt{7} \)
6\( \sqrt{4 \times 7} \) + 8\( \sqrt{7} \)
6\( \sqrt{2^2 \times 7} \) + 8\( \sqrt{7} \)
(6)(2)\( \sqrt{7} \) + 8\( \sqrt{7} \)
12\( \sqrt{7} \) + 8\( \sqrt{7} \)

Now that the radicands are identical, you can add them together:

12\( \sqrt{7} \) + 8\( \sqrt{7} \)
(12 + 8)\( \sqrt{7} \)
20\( \sqrt{7} \)