| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.18 |
| Score | 0% | 64% |
If all of a roofing company's 8 workers are required to staff 4 roofing crews, how many workers need to be added during the busy season in order to send 9 complete crews out on jobs?
| 10 | |
| 17 | |
| 5 | |
| 19 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 8 workers at the company now and that's enough to staff 4 crews so there are \( \frac{8}{4} \) = 2 workers on a crew. 9 crews are needed for the busy season which, at 2 workers per crew, means that the roofing company will need 9 x 2 = 18 total workers to staff the crews during the busy season. The company already employs 8 workers so they need to add 18 - 8 = 10 new staff for the busy season.
What is \( \frac{3}{4} \) + \( \frac{3}{6} \)?
| 1\(\frac{1}{4}\) | |
| 2 \( \frac{6}{12} \) | |
| \( \frac{5}{12} \) | |
| \( \frac{6}{12} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60]. The first few multiples they share are [12, 24, 36, 48, 60] making 12 the smallest multiple 4 and 6 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{3 x 3}{4 x 3} \) + \( \frac{3 x 2}{6 x 2} \)
\( \frac{9}{12} \) + \( \frac{6}{12} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{9 + 6}{12} \) = \( \frac{15}{12} \) = 1\(\frac{1}{4}\)
The total water usage for a city is 40,000 gallons each day. Of that total, 35% is for personal use and 66% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 550 | |
| 7,000 | |
| 4,400 | |
| 12,400 |
66% of the water consumption is industrial use and 35% is personal use so (66% - 35%) = 31% more water is used for industrial purposes. 40,000 gallons are consumed daily so industry consumes \( \frac{31}{100} \) x 40,000 gallons = 12,400 gallons.
9 members of a bridal party need transported to a wedding reception but there are only 2 4-passenger taxis available to take them. How many will need to find other transportation?
| 2 | |
| 9 | |
| 5 | |
| 1 |
There are 2 4-passenger taxis available so that's 2 x 4 = 8 total seats. There are 9 people needing transportation leaving 9 - 8 = 1 who will have to find other transportation.
What is -5b6 - 7b6?
| 2b36 | |
| 12b6 | |
| 2b12 | |
| -12b6 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:
-5b6 - 7b6
(-5 - 7)b6
-12b6