| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.93 |
| Score | 0% | 59% |
What is 9\( \sqrt{3} \) x 9\( \sqrt{6} \)?
| 243\( \sqrt{2} \) | |
| 81\( \sqrt{6} \) | |
| 81\( \sqrt{9} \) | |
| 81\( \sqrt{3} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
9\( \sqrt{3} \) x 9\( \sqrt{6} \)
(9 x 9)\( \sqrt{3 \times 6} \)
81\( \sqrt{18} \)
Now we need to simplify the radical:
81\( \sqrt{18} \)
81\( \sqrt{2 \times 9} \)
81\( \sqrt{2 \times 3^2} \)
(81)(3)\( \sqrt{2} \)
243\( \sqrt{2} \)
Which of the following is not a prime number?
9 |
|
2 |
|
7 |
|
5 |
A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.
What is \( \frac{5}{3} \) - \( \frac{7}{11} \)?
| 2 \( \frac{7}{15} \) | |
| 2 \( \frac{5}{10} \) | |
| 1\(\frac{1}{33}\) | |
| \( \frac{1}{4} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 11 are [11, 22, 33, 44, 55, 66, 77, 88, 99]. The first few multiples they share are [33, 66, 99] making 33 the smallest multiple 3 and 11 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{5 x 11}{3 x 11} \) - \( \frac{7 x 3}{11 x 3} \)
\( \frac{55}{33} \) - \( \frac{21}{33} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{55 - 21}{33} \) = \( \frac{34}{33} \) = 1\(\frac{1}{33}\)
If a mayor is elected with 78% of the votes cast and 70% of a town's 12,000 voters cast a vote, how many votes did the mayor receive?
| 6,384 | |
| 4,872 | |
| 5,964 | |
| 6,552 |
If 70% of the town's 12,000 voters cast ballots the number of votes cast is:
(\( \frac{70}{100} \)) x 12,000 = \( \frac{840,000}{100} \) = 8,400
The mayor got 78% of the votes cast which is:
(\( \frac{78}{100} \)) x 8,400 = \( \frac{655,200}{100} \) = 6,552 votes.
13 members of a bridal party need transported to a wedding reception but there are only 3 4-passenger taxis available to take them. How many will need to find other transportation?
| 2 | |
| 1 | |
| 3 | |
| 9 |
There are 3 4-passenger taxis available so that's 3 x 4 = 12 total seats. There are 13 people needing transportation leaving 13 - 12 = 1 who will have to find other transportation.