ASVAB Arithmetic Reasoning Practice Test 873458 Results

Your Results Global Average
Questions 5 5
Correct 0 2.93
Score 0% 59%

Review

1

What is 9\( \sqrt{3} \) x 9\( \sqrt{6} \)?

41% Answer Correctly
243\( \sqrt{2} \)
81\( \sqrt{6} \)
81\( \sqrt{9} \)
81\( \sqrt{3} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

9\( \sqrt{3} \) x 9\( \sqrt{6} \)
(9 x 9)\( \sqrt{3 \times 6} \)
81\( \sqrt{18} \)

Now we need to simplify the radical:

81\( \sqrt{18} \)
81\( \sqrt{2 \times 9} \)
81\( \sqrt{2 \times 3^2} \)
(81)(3)\( \sqrt{2} \)
243\( \sqrt{2} \)


2

Which of the following is not a prime number?

65% Answer Correctly

9

2

7

5


Solution

A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.


3

What is \( \frac{5}{3} \) - \( \frac{7}{11} \)?

61% Answer Correctly
2 \( \frac{7}{15} \)
2 \( \frac{5}{10} \)
1\(\frac{1}{33}\)
\( \frac{1}{4} \)

Solution

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 11 are [11, 22, 33, 44, 55, 66, 77, 88, 99]. The first few multiples they share are [33, 66, 99] making 33 the smallest multiple 3 and 11 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{5 x 11}{3 x 11} \) - \( \frac{7 x 3}{11 x 3} \)

\( \frac{55}{33} \) - \( \frac{21}{33} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{55 - 21}{33} \) = \( \frac{34}{33} \) = 1\(\frac{1}{33}\)


4

If a mayor is elected with 78% of the votes cast and 70% of a town's 12,000 voters cast a vote, how many votes did the mayor receive?

49% Answer Correctly
6,384
4,872
5,964
6,552

Solution

If 70% of the town's 12,000 voters cast ballots the number of votes cast is:

(\( \frac{70}{100} \)) x 12,000 = \( \frac{840,000}{100} \) = 8,400

The mayor got 78% of the votes cast which is:

(\( \frac{78}{100} \)) x 8,400 = \( \frac{655,200}{100} \) = 6,552 votes.


5

13 members of a bridal party need transported to a wedding reception but there are only 3 4-passenger taxis available to take them. How many will need to find other transportation?

75% Answer Correctly
2
1
3
9

Solution

There are 3 4-passenger taxis available so that's 3 x 4 = 12 total seats. There are 13 people needing transportation leaving 13 - 12 = 1 who will have to find other transportation.