ASVAB Arithmetic Reasoning Practice Test 874117 Results

Your Results Global Average
Questions 5 5
Correct 0 3.01
Score 0% 60%

Review

1

Which of the following is not a prime number?

64% Answer Correctly

2

9

5

7


Solution

A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.


2

What is 3\( \sqrt{6} \) x 2\( \sqrt{3} \)?

41% Answer Correctly
6\( \sqrt{3} \)
6\( \sqrt{9} \)
18\( \sqrt{2} \)
5\( \sqrt{18} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

3\( \sqrt{6} \) x 2\( \sqrt{3} \)
(3 x 2)\( \sqrt{6 \times 3} \)
6\( \sqrt{18} \)

Now we need to simplify the radical:

6\( \sqrt{18} \)
6\( \sqrt{2 \times 9} \)
6\( \sqrt{2 \times 3^2} \)
(6)(3)\( \sqrt{2} \)
18\( \sqrt{2} \)


3

Which of the following is a mixed number?

82% Answer Correctly

\(1 {2 \over 5} \)

\({7 \over 5} \)

\({5 \over 7} \)

\({a \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


4

What is \( \frac{-4y^9}{5y^3} \)?

60% Answer Correctly
-\(\frac{4}{5}\)y6
-\(\frac{4}{5}\)y27
-1\(\frac{1}{4}\)y12
-1\(\frac{1}{4}\)y-6

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-4y^9}{5y^3} \)
\( \frac{-4}{5} \) y(9 - 3)
-\(\frac{4}{5}\)y6


5

A circular logo is enlarged to fit the lid of a jar. The new diameter is 65% larger than the original. By what percentage has the area of the logo increased?

50% Answer Correctly
25%
32\(\frac{1}{2}\)%
22\(\frac{1}{2}\)%
35%

Solution

The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 65% the radius (and, consequently, the total area) increases by \( \frac{65\text{%}}{2} \) = 32\(\frac{1}{2}\)%