ASVAB Arithmetic Reasoning Practice Test 875220 Results

Your Results Global Average
Questions 5 5
Correct 0 3.24
Score 0% 65%

Review

1

What is the distance in miles of a trip that takes 7 hours at an average speed of 25 miles per hour?

87% Answer Correctly
175 miles
495 miles
280 miles
75 miles

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for distance:

distance = \( \text{speed} \times \text{time} \)
distance = \( 25mph \times 7h \)
175 miles


2

If \(\left|a\right| = 7\), which of the following best describes a?

67% Answer Correctly

a = 7 or a = -7

none of these is correct

a = 7

a = -7


Solution

The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).


3

What is \( 2 \)\( \sqrt{175} \) + \( 2 \)\( \sqrt{7} \)

35% Answer Correctly
4\( \sqrt{7} \)
4\( \sqrt{25} \)
4\( \sqrt{175} \)
12\( \sqrt{7} \)

Solution

To add these radicals together their radicands must be the same:

2\( \sqrt{175} \) + 2\( \sqrt{7} \)
2\( \sqrt{25 \times 7} \) + 2\( \sqrt{7} \)
2\( \sqrt{5^2 \times 7} \) + 2\( \sqrt{7} \)
(2)(5)\( \sqrt{7} \) + 2\( \sqrt{7} \)
10\( \sqrt{7} \) + 2\( \sqrt{7} \)

Now that the radicands are identical, you can add them together:

10\( \sqrt{7} \) + 2\( \sqrt{7} \)
(10 + 2)\( \sqrt{7} \)
12\( \sqrt{7} \)


4

Solve for \( \frac{3!}{4!} \)

67% Answer Correctly
56
\( \frac{1}{4} \)
1680
6720

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{3!}{4!} \)
\( \frac{3 \times 2 \times 1}{4 \times 3 \times 2 \times 1} \)
\( \frac{1}{4} \)
\( \frac{1}{4} \)


5

Convert y-5 to remove the negative exponent.

68% Answer Correctly
\( \frac{5}{y} \)
\( \frac{1}{y^5} \)
\( \frac{-5}{y} \)
\( \frac{1}{y^{-5}} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.