To add these radicals together their radicands must be the same:

7\( \sqrt{112} \) + 9\( \sqrt{7} \)
7\( \sqrt{16 \times 7} \) + 9\( \sqrt{7} \)
7\( \sqrt{4^2 \times 7} \) + 9\( \sqrt{7} \)
(7)(4)\( \sqrt{7} \) + 9\( \sqrt{7} \)
28\( \sqrt{7} \) + 9\( \sqrt{7} \)

Now that the radicands are identical, you can add them together:

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-7y^6}{3y^4} \)
\( \frac{-7}{3} \) y^{(6 - 4)}
-2\(\frac{1}{3}\)y²

guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 20 x \( \frac{65}{100} \) = \( \frac{65 x 20}{100} \) = \( \frac{1300}{100} \) = 13 shots

The center makes 45% of his shots so he'll have to take:

shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)

to make as many shots as the guard. Plugging in values for the center gives us:

center shots taken = \( \frac{13}{\frac{45}{100}} \) = 13 x \( \frac{100}{45} \) = \( \frac{13 x 100}{45} \) = \( \frac{1300}{45} \) = 29 shots

to make the same number of shots as the guard and thus score the same number of points.

A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.