ASVAB Arithmetic Reasoning Practice Test 880871 Results

Your Results Global Average
Questions 5 5
Correct 0 3.57
Score 0% 71%

Review

1

What is y7 x 7y5?

75% Answer Correctly
8y5
7y7
8y35
7y12

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

y7 x 7y5
(1 x 7)y(7 + 5)
7y12


2

What is \( \frac{2}{7} \) x \( \frac{1}{8} \)?

72% Answer Correctly
\(\frac{1}{28}\)
\(\frac{1}{4}\)
\(\frac{1}{9}\)
\(\frac{1}{14}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{2}{7} \) x \( \frac{1}{8} \) = \( \frac{2 x 1}{7 x 8} \) = \( \frac{2}{56} \) = \(\frac{1}{28}\)


3

What is \( \sqrt{\frac{81}{16}} \)?

70% Answer Correctly
1\(\frac{1}{3}\)
2\(\frac{1}{4}\)
3\(\frac{1}{2}\)
\(\frac{3}{7}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{81}{16}} \)
\( \frac{\sqrt{81}}{\sqrt{16}} \)
\( \frac{\sqrt{9^2}}{\sqrt{4^2}} \)
\( \frac{9}{4} \)
2\(\frac{1}{4}\)


4

Which of the following is a mixed number?

82% Answer Correctly

\({7 \over 5} \)

\({5 \over 7} \)

\(1 {2 \over 5} \)

\({a \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


5

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

56% Answer Correctly

distributive property for multiplication

commutative property for division

commutative property for multiplication

distributive property for division


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).