| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.03 |
| Score | 0% | 61% |
What is \( \frac{1}{9} \) x \( \frac{1}{7} \)?
| \(\frac{4}{15}\) | |
| \(\frac{3}{20}\) | |
| \(\frac{1}{63}\) | |
| \(\frac{1}{7}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{1}{9} \) x \( \frac{1}{7} \) = \( \frac{1 x 1}{9 x 7} \) = \( \frac{1}{63} \) = \(\frac{1}{63}\)
Which of the following is not a prime number?
7 |
|
9 |
|
5 |
|
2 |
A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.
The total water usage for a city is 40,000 gallons each day. Of that total, 13% is for personal use and 28% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 13,000 | |
| 2,800 | |
| 3,000 | |
| 6,000 |
28% of the water consumption is industrial use and 13% is personal use so (28% - 13%) = 15% more water is used for industrial purposes. 40,000 gallons are consumed daily so industry consumes \( \frac{15}{100} \) x 40,000 gallons = 6,000 gallons.
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 10% off." If Bob buys two shirts, each with a regular price of $46, how much will he pay for both shirts?
| $87.40 | |
| $64.40 | |
| $59.80 | |
| $41.40 |
By buying two shirts, Bob will save $46 x \( \frac{10}{100} \) = \( \frac{$46 x 10}{100} \) = \( \frac{$460}{100} \) = $4.60 on the second shirt.
So, his total cost will be
$46.00 + ($46.00 - $4.60)
$46.00 + $41.40
$87.40
A machine in a factory has an error rate of 9 parts per 100. The machine normally runs 24 hours a day and produces 6 parts per hour. Yesterday the machine was shut down for 6 hours for maintenance.
How many error-free parts did the machine produce yesterday?
| 98.3 | |
| 104.9 | |
| 157.3 | |
| 188 |
The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:
\( \frac{9}{100} \) x 6 = \( \frac{9 \times 6}{100} \) = \( \frac{54}{100} \) = 0.54 errors per hour
So, in an average hour, the machine will produce 6 - 0.54 = 5.46 error free parts.
The machine ran for 24 - 6 = 18 hours yesterday so you would expect that 18 x 5.46 = 98.3 error free parts were produced yesterday.