| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.94 |
| Score | 0% | 59% |
April scored 80% on her final exam. If each question was worth 4 points and there were 120 possible points on the exam, how many questions did April answer correctly?
| 25 | |
| 19 | |
| 24 | |
| 14 |
April scored 80% on the test meaning she earned 80% of the possible points on the test. There were 120 possible points on the test so she earned 120 x 0.8 = 96 points. Each question is worth 4 points so she got \( \frac{96}{4} \) = 24 questions right.
What is the least common multiple of 8 and 12?
| 41 | |
| 32 | |
| 58 | |
| 24 |
The first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80] and the first few multiples of 12 are [12, 24, 36, 48, 60, 72, 84, 96]. The first few multiples they share are [24, 48, 72, 96] making 24 the smallest multiple 8 and 12 have in common.
On average, the center for a basketball team hits 30% of his shots while a guard on the same team hits 40% of his shots. If the guard takes 20 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 15 | |
| 27 | |
| 16 | |
| 18 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 20 x \( \frac{40}{100} \) = \( \frac{40 x 20}{100} \) = \( \frac{800}{100} \) = 8 shots
The center makes 30% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{8}{\frac{30}{100}} \) = 8 x \( \frac{100}{30} \) = \( \frac{8 x 100}{30} \) = \( \frac{800}{30} \) = 27 shots
to make the same number of shots as the guard and thus score the same number of points.
What is 5\( \sqrt{3} \) x 2\( \sqrt{5} \)?
| 10\( \sqrt{15} \) | |
| 10\( \sqrt{5} \) | |
| 7\( \sqrt{15} \) | |
| 7\( \sqrt{3} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
5\( \sqrt{3} \) x 2\( \sqrt{5} \)
(5 x 2)\( \sqrt{3 \times 5} \)
10\( \sqrt{15} \)
Simplify \( \frac{40}{60} \).
| \( \frac{8}{11} \) | |
| \( \frac{8}{17} \) | |
| \( \frac{2}{3} \) | |
| \( \frac{7}{12} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 40 are [1, 2, 4, 5, 8, 10, 20, 40] and the factors of 60 are [1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60]. They share 6 factors [1, 2, 4, 5, 10, 20] making 20 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{40}{60} \) = \( \frac{\frac{40}{20}}{\frac{60}{20}} \) = \( \frac{2}{3} \)