ASVAB Arithmetic Reasoning Practice Test 884898 Results

Your Results Global Average
Questions 5 5
Correct 0 3.22
Score 0% 64%

Review

1

What is the distance in miles of a trip that takes 4 hours at an average speed of 45 miles per hour?

87% Answer Correctly
200 miles
180 miles
50 miles
160 miles

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for distance:

distance = \( \text{speed} \times \text{time} \)
distance = \( 45mph \times 4h \)
180 miles


2

What is \( \frac{2}{8} \) ÷ \( \frac{1}{7} \)?

68% Answer Correctly
1\(\frac{3}{4}\)
\(\frac{1}{14}\)
14
\(\frac{2}{35}\)

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{2}{8} \) ÷ \( \frac{1}{7} \) = \( \frac{2}{8} \) x \( \frac{7}{1} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{2}{8} \) x \( \frac{7}{1} \) = \( \frac{2 x 7}{8 x 1} \) = \( \frac{14}{8} \) = 1\(\frac{3}{4}\)


3

What is 4\( \sqrt{8} \) x 2\( \sqrt{2} \)?

41% Answer Correctly
8\( \sqrt{2} \)
32
6\( \sqrt{2} \)
6\( \sqrt{16} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

4\( \sqrt{8} \) x 2\( \sqrt{2} \)
(4 x 2)\( \sqrt{8 \times 2} \)
8\( \sqrt{16} \)

Now we need to simplify the radical:

8\( \sqrt{16} \)
8\( \sqrt{4^2} \)
(8)(4)
32


4

If \(\left|a\right| = 7\), which of the following best describes a?

67% Answer Correctly

a = 7

none of these is correct

a = -7

a = 7 or a = -7


Solution

The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).


5

What is \( \frac{-8c^6}{4c^2} \)?

60% Answer Correctly
-2c-4
-2c4
-\(\frac{1}{2}\)c-4
-\(\frac{1}{2}\)c8

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-8c^6}{4c^2} \)
\( \frac{-8}{4} \) c(6 - 2)
-2c4