| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.03 |
| Score | 0% | 61% |
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 25% off." If Charlie buys two shirts, each with a regular price of $43, how much will he pay for both shirts?
| $75.25 | |
| $58.05 | |
| $60.20 | |
| $64.50 |
By buying two shirts, Charlie will save $43 x \( \frac{25}{100} \) = \( \frac{$43 x 25}{100} \) = \( \frac{$1075}{100} \) = $10.75 on the second shirt.
So, his total cost will be
$43.00 + ($43.00 - $10.75)
$43.00 + $32.25
$75.25
The __________ is the smallest positive integer that is a multiple of two or more integers.
least common multiple |
|
least common factor |
|
absolute value |
|
greatest common factor |
The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.
Monty loaned Latoya $600 at an annual interest rate of 9%. If no payments are made, what is the total amount owed at the end of the first year?
| $612 | |
| $654 | |
| $648 | |
| $636 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $600
i = 0.09 x $600
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $600 + $54What is b5 x 6b6?
| 7b5 | |
| 6b5 | |
| 6b11 | |
| 6b6 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
b5 x 6b6
(1 x 6)b(5 + 6)
6b11
If a rectangle is twice as long as it is wide and has a perimeter of 12 meters, what is the area of the rectangle?
| 98 m2 | |
| 8 m2 | |
| 162 m2 | |
| 18 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 12 meters so the equation becomes: 2w + 2h = 12.
Putting these two equations together and solving for width (w):
2w + 2h = 12
w + h = \( \frac{12}{2} \)
w + h = 6
w = 6 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 6 - 2w
3w = 6
w = \( \frac{6}{3} \)
w = 2
Since h = 2w that makes h = (2 x 2) = 4 and the area = h x w = 2 x 4 = 8 m2