| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.85 |
| Score | 0% | 57% |
On average, the center for a basketball team hits 50% of his shots while a guard on the same team hits 65% of his shots. If the guard takes 15 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 33 | |
| 18 | |
| 28 | |
| 26 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 15 x \( \frac{65}{100} \) = \( \frac{65 x 15}{100} \) = \( \frac{975}{100} \) = 9 shots
The center makes 50% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{9}{\frac{50}{100}} \) = 9 x \( \frac{100}{50} \) = \( \frac{9 x 100}{50} \) = \( \frac{900}{50} \) = 18 shots
to make the same number of shots as the guard and thus score the same number of points.
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
commutative property for multiplication |
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distributive property for multiplication |
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distributive property for division |
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commutative property for division |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
What is \( \sqrt{\frac{36}{64}} \)?
| 2 | |
| \(\frac{4}{9}\) | |
| \(\frac{1}{3}\) | |
| \(\frac{3}{4}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{36}{64}} \)
\( \frac{\sqrt{36}}{\sqrt{64}} \)
\( \frac{\sqrt{6^2}}{\sqrt{8^2}} \)
\(\frac{3}{4}\)
If a mayor is elected with 61% of the votes cast and 77% of a town's 43,000 voters cast a vote, how many votes did the mayor receive?
| 24,501 | |
| 19,535 | |
| 20,197 | |
| 29,468 |
If 77% of the town's 43,000 voters cast ballots the number of votes cast is:
(\( \frac{77}{100} \)) x 43,000 = \( \frac{3,311,000}{100} \) = 33,110
The mayor got 61% of the votes cast which is:
(\( \frac{61}{100} \)) x 33,110 = \( \frac{2,019,710}{100} \) = 20,197 votes.
Solve for \( \frac{2!}{6!} \)
| \( \frac{1}{360} \) | |
| 5 | |
| \( \frac{1}{72} \) | |
| \( \frac{1}{30} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{2!}{6!} \)
\( \frac{2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6 \times 5 \times 4 \times 3} \)
\( \frac{1}{360} \)