| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.73 |
| Score | 0% | 55% |
On average, the center for a basketball team hits 25% of his shots while a guard on the same team hits 35% of his shots. If the guard takes 30 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 40 | |
| 17 | |
| 22 | |
| 45 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 30 x \( \frac{35}{100} \) = \( \frac{35 x 30}{100} \) = \( \frac{1050}{100} \) = 10 shots
The center makes 25% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{10}{\frac{25}{100}} \) = 10 x \( \frac{100}{25} \) = \( \frac{10 x 100}{25} \) = \( \frac{1000}{25} \) = 40 shots
to make the same number of shots as the guard and thus score the same number of points.
Which of the following is an improper fraction?
\(1 {2 \over 5} \) |
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\({2 \over 5} \) |
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\({7 \over 5} \) |
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\({a \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
| 0.9 | |
| 0.8 | |
| 4.8 | |
| 1 |
1
The __________ is the greatest factor that divides two integers.
greatest common multiple |
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greatest common factor |
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absolute value |
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least common multiple |
The greatest common factor (GCF) is the greatest factor that divides two integers.
What is \( 7 \)\( \sqrt{112} \) + \( 8 \)\( \sqrt{7} \)
| 15\( \sqrt{112} \) | |
| 36\( \sqrt{7} \) | |
| 15\( \sqrt{7} \) | |
| 15\( \sqrt{16} \) |
To add these radicals together their radicands must be the same:
7\( \sqrt{112} \) + 8\( \sqrt{7} \)
7\( \sqrt{16 \times 7} \) + 8\( \sqrt{7} \)
7\( \sqrt{4^2 \times 7} \) + 8\( \sqrt{7} \)
(7)(4)\( \sqrt{7} \) + 8\( \sqrt{7} \)
28\( \sqrt{7} \) + 8\( \sqrt{7} \)
Now that the radicands are identical, you can add them together:
28\( \sqrt{7} \) + 8\( \sqrt{7} \)