ASVAB Arithmetic Reasoning Practice Test 891393 Results

Your Results Global Average
Questions 5 5
Correct 0 2.96
Score 0% 59%

Review

1

What is (b2)3?

79% Answer Correctly
b-1
b6
2b3
3b2

Solution

To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

(b2)3
b(2 * 3)
b6


2

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

55% Answer Correctly

commutative property for multiplication

distributive property for multiplication

distributive property for division

commutative property for division


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).


3

How many 1 gallon cans worth of fuel would you need to pour into an empty 6 gallon tank to fill it exactly halfway?

52% Answer Correctly
3
7
6
5

Solution

To fill a 6 gallon tank exactly halfway you'll need 3 gallons of fuel. Each fuel can holds 1 gallons so:

cans = \( \frac{3 \text{ gallons}}{1 \text{ gallons}} \) = 3


4

A circular logo is enlarged to fit the lid of a jar. The new diameter is 30% larger than the original. By what percentage has the area of the logo increased?

50% Answer Correctly
35%
32\(\frac{1}{2}\)%
22\(\frac{1}{2}\)%
15%

Solution

The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 30% the radius (and, consequently, the total area) increases by \( \frac{30\text{%}}{2} \) = 15%


5

What is \( \frac{8}{6} \) + \( \frac{8}{10} \)?

59% Answer Correctly
1 \( \frac{6}{30} \)
2\(\frac{2}{15}\)
\( \frac{9}{13} \)
2 \( \frac{6}{15} \)

Solution

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [30, 60, 90] making 30 the smallest multiple 6 and 10 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{8 x 5}{6 x 5} \) + \( \frac{8 x 3}{10 x 3} \)

\( \frac{40}{30} \) + \( \frac{24}{30} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{40 + 24}{30} \) = \( \frac{64}{30} \) = 2\(\frac{2}{15}\)