ASVAB Arithmetic Reasoning Practice Test 892305 Results

Your Results Global Average
Questions 5 5
Correct 0 3.40
Score 0% 68%

Review

1

Solve 2 + (2 + 3) ÷ 2 x 4 - 32

53% Answer Correctly
3
2\(\frac{1}{4}\)
1
\(\frac{5}{6}\)

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

2 + (2 + 3) ÷ 2 x 4 - 32
P: 2 + (5) ÷ 2 x 4 - 32
E: 2 + 5 ÷ 2 x 4 - 9
MD: 2 + \( \frac{5}{2} \) x 4 - 9
MD: 2 + \( \frac{20}{2} \) - 9
AS: \( \frac{4}{2} \) + \( \frac{20}{2} \) - 9
AS: \( \frac{24}{2} \) - 9
AS: \( \frac{24 - 18}{2} \)
\( \frac{6}{2} \)
3


2

Convert 0.0008153 to scientific notation.

62% Answer Correctly
81.53 x 10-5
0.815 x 10-3
8.153 x 10-4
8.153 x 105

Solution

A number in scientific notation has the format 0.000 x 10exponent. To convert to scientific notation, move the decimal point to the right or the left until the number is a decimal between 1 and 10. The exponent of the 10 is the number of places you moved the decimal point and is positive if you moved the decimal point to the left and negative if you moved it to the right:

0.0008153 in scientific notation is 8.153 x 10-4


3

A triathlon course includes a 100m swim, a 30.2km bike ride, and a 7.6000000000000005km run. What is the total length of the race course?

69% Answer Correctly
31km
50.4km
37.9km
47.8km

Solution

To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 100 meters to kilometers, divide the distance by 1000 to get 0.1km then add the remaining distances:

total distance = swim + bike + run
total distance = 0.1km + 30.2km + 7.6000000000000005km
total distance = 37.9km


4

How many hours does it take a car to travel 50 miles at an average speed of 25 miles per hour?

86% Answer Correctly
2 hours
8 hours
5 hours
4 hours

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for time:

time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{50mi}{25mph} \)
2 hours


5

What is the least common multiple of 5 and 7?

72% Answer Correctly
5
35
10
6

Solution

The first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50] and the first few multiples of 7 are [7, 14, 21, 28, 35, 42, 49, 56, 63, 70]. The first few multiples they share are [35, 70] making 35 the smallest multiple 5 and 7 have in common.