| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.64 |
| Score | 0% | 53% |
What is \( 7 \)\( \sqrt{8} \) + \( 6 \)\( \sqrt{2} \)
| 42\( \sqrt{16} \) | |
| 13\( \sqrt{4} \) | |
| 42\( \sqrt{4} \) | |
| 20\( \sqrt{2} \) |
To add these radicals together their radicands must be the same:
7\( \sqrt{8} \) + 6\( \sqrt{2} \)
7\( \sqrt{4 \times 2} \) + 6\( \sqrt{2} \)
7\( \sqrt{2^2 \times 2} \) + 6\( \sqrt{2} \)
(7)(2)\( \sqrt{2} \) + 6\( \sqrt{2} \)
14\( \sqrt{2} \) + 6\( \sqrt{2} \)
Now that the radicands are identical, you can add them together:
14\( \sqrt{2} \) + 6\( \sqrt{2} \)Monica scored 89% on her final exam. If each question was worth 3 points and there were 240 possible points on the exam, how many questions did Monica answer correctly?
| 69 | |
| 80 | |
| 72 | |
| 71 |
Monica scored 89% on the test meaning she earned 89% of the possible points on the test. There were 240 possible points on the test so she earned 240 x 0.89 = 213 points. Each question is worth 3 points so she got \( \frac{213}{3} \) = 71 questions right.
Solve 4 + (3 + 3) ÷ 2 x 3 - 22
| 9 | |
| \(\frac{1}{3}\) | |
| \(\frac{4}{9}\) | |
| 1\(\frac{2}{5}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
4 + (3 + 3) ÷ 2 x 3 - 22
P: 4 + (6) ÷ 2 x 3 - 22
E: 4 + 6 ÷ 2 x 3 - 4
MD: 4 + \( \frac{6}{2} \) x 3 - 4
MD: 4 + \( \frac{18}{2} \) - 4
AS: \( \frac{8}{2} \) + \( \frac{18}{2} \) - 4
AS: \( \frac{26}{2} \) - 4
AS: \( \frac{26 - 8}{2} \)
\( \frac{18}{2} \)
9
If a mayor is elected with 63% of the votes cast and 75% of a town's 19,000 voters cast a vote, how many votes did the mayor receive?
| 10,545 | |
| 7,980 | |
| 8,978 | |
| 11,400 |
If 75% of the town's 19,000 voters cast ballots the number of votes cast is:
(\( \frac{75}{100} \)) x 19,000 = \( \frac{1,425,000}{100} \) = 14,250
The mayor got 63% of the votes cast which is:
(\( \frac{63}{100} \)) x 14,250 = \( \frac{897,750}{100} \) = 8,978 votes.
What is \( \sqrt{\frac{9}{4}} \)?
| 1\(\frac{1}{5}\) | |
| 1\(\frac{2}{7}\) | |
| 1\(\frac{1}{2}\) | |
| \(\frac{1}{2}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{9}{4}} \)
\( \frac{\sqrt{9}}{\sqrt{4}} \)
\( \frac{\sqrt{3^2}}{\sqrt{2^2}} \)
\( \frac{3}{2} \)
1\(\frac{1}{2}\)