| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.43 |
| Score | 0% | 69% |
| 1 | |
| 1.2 | |
| 6.3 | |
| 1.8 |
1
What is the next number in this sequence: 1, 3, 5, 7, 9, __________ ?
| 10 | |
| 17 | |
| 8 | |
| 11 |
The equation for this sequence is:
an = an-1 + 2
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 2
a6 = 9 + 2
a6 = 11
If a rectangle is twice as long as it is wide and has a perimeter of 54 meters, what is the area of the rectangle?
| 2 m2 | |
| 72 m2 | |
| 8 m2 | |
| 162 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 54 meters so the equation becomes: 2w + 2h = 54.
Putting these two equations together and solving for width (w):
2w + 2h = 54
w + h = \( \frac{54}{2} \)
w + h = 27
w = 27 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 27 - 2w
3w = 27
w = \( \frac{27}{3} \)
w = 9
Since h = 2w that makes h = (2 x 9) = 18 and the area = h x w = 9 x 18 = 162 m2
Find the average of the following numbers: 13, 9, 12, 10.
| 11 | |
| 8 | |
| 6 | |
| 15 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{13 + 9 + 12 + 10}{4} \) = \( \frac{44}{4} \) = 11
14 members of a bridal party need transported to a wedding reception but there are only 2 5-passenger taxis available to take them. How many will need to find other transportation?
| 6 | |
| 4 | |
| 5 | |
| 8 |
There are 2 5-passenger taxis available so that's 2 x 5 = 10 total seats. There are 14 people needing transportation leaving 14 - 10 = 4 who will have to find other transportation.