ASVAB Arithmetic Reasoning Practice Test 893633 Results

Your Results Global Average
Questions 5 5
Correct 0 3.27
Score 0% 65%

Review

1

Alex loaned Jennifer $100 at an annual interest rate of 8%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly
$107
$108
$103
$109

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $100
i = 0.08 x $100

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $100 + $8
total = $108


2

What is the distance in miles of a trip that takes 4 hours at an average speed of 40 miles per hour?

87% Answer Correctly
40 miles
300 miles
160 miles
560 miles

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for distance:

distance = \( \text{speed} \times \text{time} \)
distance = \( 40mph \times 4h \)
160 miles


3

A factor is a positive __________ that divides evenly into a given number.

78% Answer Correctly

improper fraction

integer

mixed number

fraction


Solution

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.


4

Solve 4 + (3 + 2) ÷ 5 x 3 - 42

52% Answer Correctly
\(\frac{3}{8}\)
2
-9
\(\frac{3}{4}\)

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

4 + (3 + 2) ÷ 5 x 3 - 42
P: 4 + (5) ÷ 5 x 3 - 42
E: 4 + 5 ÷ 5 x 3 - 16
MD: 4 + \( \frac{5}{5} \) x 3 - 16
MD: 4 + \( \frac{15}{5} \) - 16
AS: \( \frac{20}{5} \) + \( \frac{15}{5} \) - 16
AS: \( \frac{35}{5} \) - 16
AS: \( \frac{35 - 80}{5} \)
\( \frac{-45}{5} \)
-9


5

What is \( 2 \)\( \sqrt{50} \) - \( 3 \)\( \sqrt{2} \)

38% Answer Correctly
-1\( \sqrt{50} \)
6\( \sqrt{25} \)
7\( \sqrt{2} \)
6\( \sqrt{2} \)

Solution

To subtract these radicals together their radicands must be the same:

2\( \sqrt{50} \) - 3\( \sqrt{2} \)
2\( \sqrt{25 \times 2} \) - 3\( \sqrt{2} \)
2\( \sqrt{5^2 \times 2} \) - 3\( \sqrt{2} \)
(2)(5)\( \sqrt{2} \) - 3\( \sqrt{2} \)
10\( \sqrt{2} \) - 3\( \sqrt{2} \)

Now that the radicands are identical, you can subtract them:

10\( \sqrt{2} \) - 3\( \sqrt{2} \)
(10 - 3)\( \sqrt{2} \)
7\( \sqrt{2} \)