| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.43 |
| Score | 0% | 69% |
14 members of a bridal party need transported to a wedding reception but there are only 3 4-passenger taxis available to take them. How many will need to find other transportation?
| 2 | |
| 7 | |
| 9 | |
| 5 |
There are 3 4-passenger taxis available so that's 3 x 4 = 12 total seats. There are 14 people needing transportation leaving 14 - 12 = 2 who will have to find other transportation.
Which of the following is an improper fraction?
\({7 \over 5} \) |
|
\({a \over 5} \) |
|
\(1 {2 \over 5} \) |
|
\({2 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
A tiger in a zoo has consumed 132 pounds of food in 11 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 168 pounds?
| 6 | |
| 3 | |
| 5 | |
| 13 |
If the tiger has consumed 132 pounds of food in 11 days that's \( \frac{132}{11} \) = 12 pounds of food per day. The tiger needs to consume 168 - 132 = 36 more pounds of food to reach 168 pounds total. At 12 pounds of food per day that's \( \frac{36}{12} \) = 3 more days.
What is the least common multiple of 4 and 12?
| 12 | |
| 42 | |
| 2 | |
| 47 |
The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 12 are [12, 24, 36, 48, 60, 72, 84, 96]. The first few multiples they share are [12, 24, 36, 48, 60] making 12 the smallest multiple 4 and 12 have in common.
What is \( \sqrt{\frac{9}{36}} \)?
| 1\(\frac{1}{2}\) | |
| \(\frac{5}{6}\) | |
| \(\frac{3}{4}\) | |
| \(\frac{1}{2}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{9}{36}} \)
\( \frac{\sqrt{9}}{\sqrt{36}} \)
\( \frac{\sqrt{3^2}}{\sqrt{6^2}} \)
\(\frac{1}{2}\)