ASVAB Arithmetic Reasoning Practice Test 894986 Results

Your Results Global Average
Questions 5 5
Correct 0 3.28
Score 0% 66%

Review

1

What is \( \sqrt{\frac{4}{64}} \)?

70% Answer Correctly
\(\frac{1}{4}\)
3
\(\frac{4}{5}\)
1

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{4}{64}} \)
\( \frac{\sqrt{4}}{\sqrt{64}} \)
\( \frac{\sqrt{2^2}}{\sqrt{8^2}} \)
\(\frac{1}{4}\)


2

53% Answer Correctly
0.3
2.4
3.6
1

Solution


1


3

Simplify \( \frac{40}{80} \).

77% Answer Correctly
\( \frac{1}{2} \)
\( \frac{9}{20} \)
\( \frac{4}{11} \)
\( \frac{8}{15} \)

Solution

To simplify this fraction, first find the greatest common factor between them. The factors of 40 are [1, 2, 4, 5, 8, 10, 20, 40] and the factors of 80 are [1, 2, 4, 5, 8, 10, 16, 20, 40, 80]. They share 8 factors [1, 2, 4, 5, 8, 10, 20, 40] making 40 their greatest common factor (GCF).

Next, divide both numerator and denominator by the GCF:

\( \frac{40}{80} \) = \( \frac{\frac{40}{40}}{\frac{80}{40}} \) = \( \frac{1}{2} \)


4

The __________ is the greatest factor that divides two integers.

67% Answer Correctly

absolute value

greatest common multiple

least common multiple

greatest common factor


Solution

The greatest common factor (GCF) is the greatest factor that divides two integers.


5

What is \( \frac{9}{8} \) + \( \frac{3}{12} \)?

60% Answer Correctly
\( \frac{9}{12} \)
1 \( \frac{3}{24} \)
1\(\frac{3}{8}\)
1 \( \frac{6}{15} \)

Solution

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80] and the first few multiples of 12 are [12, 24, 36, 48, 60, 72, 84, 96]. The first few multiples they share are [24, 48, 72, 96] making 24 the smallest multiple 8 and 12 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{9 x 3}{8 x 3} \) + \( \frac{3 x 2}{12 x 2} \)

\( \frac{27}{24} \) + \( \frac{6}{24} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{27 + 6}{24} \) = \( \frac{33}{24} \) = 1\(\frac{3}{8}\)