| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.28 |
| Score | 0% | 66% |
What is \( \sqrt{\frac{4}{64}} \)?
| \(\frac{1}{4}\) | |
| 3 | |
| \(\frac{4}{5}\) | |
| 1 |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{4}{64}} \)
\( \frac{\sqrt{4}}{\sqrt{64}} \)
\( \frac{\sqrt{2^2}}{\sqrt{8^2}} \)
\(\frac{1}{4}\)
| 0.3 | |
| 2.4 | |
| 3.6 | |
| 1 |
1
Simplify \( \frac{40}{80} \).
| \( \frac{1}{2} \) | |
| \( \frac{9}{20} \) | |
| \( \frac{4}{11} \) | |
| \( \frac{8}{15} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 40 are [1, 2, 4, 5, 8, 10, 20, 40] and the factors of 80 are [1, 2, 4, 5, 8, 10, 16, 20, 40, 80]. They share 8 factors [1, 2, 4, 5, 8, 10, 20, 40] making 40 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{40}{80} \) = \( \frac{\frac{40}{40}}{\frac{80}{40}} \) = \( \frac{1}{2} \)
The __________ is the greatest factor that divides two integers.
absolute value |
|
greatest common multiple |
|
least common multiple |
|
greatest common factor |
The greatest common factor (GCF) is the greatest factor that divides two integers.
What is \( \frac{9}{8} \) + \( \frac{3}{12} \)?
| \( \frac{9}{12} \) | |
| 1 \( \frac{3}{24} \) | |
| 1\(\frac{3}{8}\) | |
| 1 \( \frac{6}{15} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80] and the first few multiples of 12 are [12, 24, 36, 48, 60, 72, 84, 96]. The first few multiples they share are [24, 48, 72, 96] making 24 the smallest multiple 8 and 12 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{9 x 3}{8 x 3} \) + \( \frac{3 x 2}{12 x 2} \)
\( \frac{27}{24} \) + \( \frac{6}{24} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{27 + 6}{24} \) = \( \frac{33}{24} \) = 1\(\frac{3}{8}\)