| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.34 |
| Score | 0% | 67% |
Solve 3 + (2 + 2) ÷ 5 x 3 - 32
| \(\frac{5}{6}\) | |
| -3\(\frac{3}{5}\) | |
| 1\(\frac{3}{5}\) | |
| \(\frac{2}{9}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
3 + (2 + 2) ÷ 5 x 3 - 32
P: 3 + (4) ÷ 5 x 3 - 32
E: 3 + 4 ÷ 5 x 3 - 9
MD: 3 + \( \frac{4}{5} \) x 3 - 9
MD: 3 + \( \frac{12}{5} \) - 9
AS: \( \frac{15}{5} \) + \( \frac{12}{5} \) - 9
AS: \( \frac{27}{5} \) - 9
AS: \( \frac{27 - 45}{5} \)
\( \frac{-18}{5} \)
-3\(\frac{3}{5}\)
A bread recipe calls for 3\(\frac{1}{4}\) cups of flour. If you only have 1\(\frac{1}{4}\) cups, how much more flour is needed?
| 2 cups | |
| 1 cups | |
| 1\(\frac{1}{4}\) cups | |
| 1\(\frac{1}{2}\) cups |
The amount of flour you need is (3\(\frac{1}{4}\) - 1\(\frac{1}{4}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{26}{8} \) - \( \frac{10}{8} \)) cups
\( \frac{16}{8} \) cups
2 cups
Which of the following is a mixed number?
\({5 \over 7} \) |
|
\({7 \over 5} \) |
|
\({a \over 5} \) |
|
\(1 {2 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
What is the next number in this sequence: 1, 3, 7, 13, 21, __________ ?
| 31 | |
| 25 | |
| 38 | |
| 28 |
The equation for this sequence is:
an = an-1 + 2(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 2(6 - 1)
a6 = 21 + 2(5)
a6 = 31
What is x3 + x3?
| 2x9 | |
| 2x3 | |
| 3 | |
| -3 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:
1x3 + 1x3
(1 + 1)x3
2x3