ASVAB Arithmetic Reasoning Practice Test 897330 Results

Your Results Global Average
Questions 5 5
Correct 0 3.34
Score 0% 67%

Review

1

Solve 3 + (2 + 2) ÷ 5 x 3 - 32

53% Answer Correctly
\(\frac{5}{6}\)
-3\(\frac{3}{5}\)
1\(\frac{3}{5}\)
\(\frac{2}{9}\)

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

3 + (2 + 2) ÷ 5 x 3 - 32
P: 3 + (4) ÷ 5 x 3 - 32
E: 3 + 4 ÷ 5 x 3 - 9
MD: 3 + \( \frac{4}{5} \) x 3 - 9
MD: 3 + \( \frac{12}{5} \) - 9
AS: \( \frac{15}{5} \) + \( \frac{12}{5} \) - 9
AS: \( \frac{27}{5} \) - 9
AS: \( \frac{27 - 45}{5} \)
\( \frac{-18}{5} \)
-3\(\frac{3}{5}\)


2

A bread recipe calls for 3\(\frac{1}{4}\) cups of flour. If you only have 1\(\frac{1}{4}\) cups, how much more flour is needed?

62% Answer Correctly
2 cups
1 cups
1\(\frac{1}{4}\) cups
1\(\frac{1}{2}\) cups

Solution

The amount of flour you need is (3\(\frac{1}{4}\) - 1\(\frac{1}{4}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{26}{8} \) - \( \frac{10}{8} \)) cups
\( \frac{16}{8} \) cups
2 cups


3

Which of the following is a mixed number?

83% Answer Correctly

\({5 \over 7} \)

\({7 \over 5} \)

\({a \over 5} \)

\(1 {2 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


4

What is the next number in this sequence: 1, 3, 7, 13, 21, __________ ?

69% Answer Correctly
31
25
38
28

Solution

The equation for this sequence is:

an = an-1 + 2(n - 1)

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 2(6 - 1)
a6 = 21 + 2(5)
a6 = 31


5

What is x3 + x3?

66% Answer Correctly
2x9
2x3
3
-3

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

1x3 + 1x3
(1 + 1)x3
2x3