| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.29 |
| Score | 0% | 66% |
| 1 | |
| 5.6 | |
| 7.2 | |
| 1.5 |
1
What is the greatest common factor of 72 and 60?
| 12 | |
| 54 | |
| 47 | |
| 40 |
The factors of 72 are [1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72] and the factors of 60 are [1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60]. They share 6 factors [1, 2, 3, 4, 6, 12] making 12 the greatest factor 72 and 60 have in common.
How many hours does it take a car to travel 300 miles at an average speed of 75 miles per hour?
| 7 hours | |
| 2 hours | |
| 1 hour | |
| 4 hours |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for time:
time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{300mi}{75mph} \)
4 hours
What is \( \frac{5}{3} \) - \( \frac{8}{9} \)?
| 2 \( \frac{4}{9} \) | |
| \(\frac{7}{9}\) | |
| 1 \( \frac{6}{12} \) | |
| 2 \( \frac{3}{9} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [9, 18, 27, 36, 45] making 9 the smallest multiple 3 and 9 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{5 x 3}{3 x 3} \) - \( \frac{8 x 1}{9 x 1} \)
\( \frac{15}{9} \) - \( \frac{8}{9} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{15 - 8}{9} \) = \( \frac{7}{9} \) = \(\frac{7}{9}\)
A circular logo is enlarged to fit the lid of a jar. The new diameter is 60% larger than the original. By what percentage has the area of the logo increased?
| 17\(\frac{1}{2}\)% | |
| 30% | |
| 22\(\frac{1}{2}\)% | |
| 37\(\frac{1}{2}\)% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 60% the radius (and, consequently, the total area) increases by \( \frac{60\text{%}}{2} \) = 30%