ASVAB Arithmetic Reasoning Practice Test 897559 Results

Your Results Global Average
Questions 5 5
Correct 0 2.94
Score 0% 59%

Review

1

This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.

60% Answer Correctly

associative

commutative

distributive

PEDMAS


Solution

The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.


2

If \( \left|x + 7\right| \) + 8 = 4, which of these is a possible value for x?

62% Answer Correctly
13
19
-3
-4

Solution

First, solve for \( \left|x + 7\right| \):

\( \left|x + 7\right| \) + 8 = 4
\( \left|x + 7\right| \) = 4 - 8
\( \left|x + 7\right| \) = -4

The value inside the absolute value brackets can be either positive or negative so (x + 7) must equal - 4 or --4 for \( \left|x + 7\right| \) to equal -4:

x + 7 = -4
x = -4 - 7
x = -11
x + 7 = 4
x = 4 - 7
x = -3

So, x = -3 or x = -11.


3

Which of the following statements about exponents is false?

47% Answer Correctly

b1 = b

b0 = 1

b1 = 1

all of these are false


Solution

A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).


4

Which of the following is not an integer?

77% Answer Correctly

1

0

\({1 \over 2}\)

-1


Solution

An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.


5

If a rectangle is twice as long as it is wide and has a perimeter of 36 meters, what is the area of the rectangle?

47% Answer Correctly
72 m2
50 m2
128 m2
98 m2

Solution

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 36 meters so the equation becomes: 2w + 2h = 36.

Putting these two equations together and solving for width (w):

2w + 2h = 36
w + h = \( \frac{36}{2} \)
w + h = 18
w = 18 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 18 - 2w
3w = 18
w = \( \frac{18}{3} \)
w = 6

Since h = 2w that makes h = (2 x 6) = 12 and the area = h x w = 6 x 12 = 72 m2