| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.49 |
| Score | 0% | 70% |
Ezra loaned Betty $1,200 at an annual interest rate of 6%. If no payments are made, what is the total amount owed at the end of the first year?
| $1,308 | |
| $1,212 | |
| $1,236 | |
| $1,272 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,200
i = 0.06 x $1,200
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $1,200 + $72The total water usage for a city is 20,000 gallons each day. Of that total, 20% is for personal use and 32% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 5,250 | |
| 2,400 | |
| 1,700 | |
| 3,300 |
32% of the water consumption is industrial use and 20% is personal use so (32% - 20%) = 12% more water is used for industrial purposes. 20,000 gallons are consumed daily so industry consumes \( \frac{12}{100} \) x 20,000 gallons = 2,400 gallons.
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 15% off." If Damon buys two shirts, each with a regular price of $50, how much will he pay for both shirts?
| $52.50 | |
| $70.00 | |
| $92.50 | |
| $55.00 |
By buying two shirts, Damon will save $50 x \( \frac{15}{100} \) = \( \frac{$50 x 15}{100} \) = \( \frac{$750}{100} \) = $7.50 on the second shirt.
So, his total cost will be
$50.00 + ($50.00 - $7.50)
$50.00 + $42.50
$92.50
Simplify \( \frac{40}{56} \).
| \( \frac{9}{11} \) | |
| \( \frac{5}{11} \) | |
| \( \frac{3}{7} \) | |
| \( \frac{5}{7} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 40 are [1, 2, 4, 5, 8, 10, 20, 40] and the factors of 56 are [1, 2, 4, 7, 8, 14, 28, 56]. They share 4 factors [1, 2, 4, 8] making 8 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{40}{56} \) = \( \frac{\frac{40}{8}}{\frac{56}{8}} \) = \( \frac{5}{7} \)
How many hours does it take a car to travel 525 miles at an average speed of 75 miles per hour?
| 6 hours | |
| 7 hours | |
| 2 hours | |
| 4 hours |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for time:
time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{525mi}{75mph} \)
7 hours