ASVAB Arithmetic Reasoning Practice Test 899118 Results

Your Results Global Average
Questions 5 5
Correct 0 3.02
Score 0% 60%

Review

1

If the ratio of home fans to visiting fans in a crowd is 5:1 and all 41,000 seats in a stadium are filled, how many home fans are in attendance?

50% Answer Correctly
34,167
27,200
27,750
20,667

Solution

A ratio of 5:1 means that there are 5 home fans for every one visiting fan. So, of every 6 fans, 5 are home fans and \( \frac{5}{6} \) of every fan in the stadium is a home fan:

41,000 fans x \( \frac{5}{6} \) = \( \frac{205000}{6} \) = 34,167 fans.


2

Which of these numbers is a factor of 64?

68% Answer Correctly
26
54
64
41

Solution

The factors of a number are all positive integers that divide evenly into the number. The factors of 64 are 1, 2, 4, 8, 16, 32, 64.


3

Which of the following is a mixed number?

82% Answer Correctly

\({a \over 5} \)

\(1 {2 \over 5} \)

\({5 \over 7} \)

\({7 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


4

What is \( 6 \)\( \sqrt{80} \) - \( 7 \)\( \sqrt{5} \)

38% Answer Correctly
42\( \sqrt{80} \)
17\( \sqrt{5} \)
-1\( \sqrt{9} \)
42\( \sqrt{16} \)

Solution

To subtract these radicals together their radicands must be the same:

6\( \sqrt{80} \) - 7\( \sqrt{5} \)
6\( \sqrt{16 \times 5} \) - 7\( \sqrt{5} \)
6\( \sqrt{4^2 \times 5} \) - 7\( \sqrt{5} \)
(6)(4)\( \sqrt{5} \) - 7\( \sqrt{5} \)
24\( \sqrt{5} \) - 7\( \sqrt{5} \)

Now that the radicands are identical, you can subtract them:

24\( \sqrt{5} \) - 7\( \sqrt{5} \)
(24 - 7)\( \sqrt{5} \)
17\( \sqrt{5} \)


5

What is \( \frac{4}{4} \) + \( \frac{4}{8} \)?

59% Answer Correctly
\( \frac{6}{8} \)
1 \( \frac{6}{8} \)
1\(\frac{1}{2}\)
2 \( \frac{5}{8} \)

Solution

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80]. The first few multiples they share are [8, 16, 24, 32, 40] making 8 the smallest multiple 4 and 8 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{4 x 2}{4 x 2} \) + \( \frac{4 x 1}{8 x 1} \)

\( \frac{8}{8} \) + \( \frac{4}{8} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{8 + 4}{8} \) = \( \frac{12}{8} \) = 1\(\frac{1}{2}\)