| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.02 |
| Score | 0% | 60% |
If the ratio of home fans to visiting fans in a crowd is 5:1 and all 41,000 seats in a stadium are filled, how many home fans are in attendance?
| 34,167 | |
| 27,200 | |
| 27,750 | |
| 20,667 |
A ratio of 5:1 means that there are 5 home fans for every one visiting fan. So, of every 6 fans, 5 are home fans and \( \frac{5}{6} \) of every fan in the stadium is a home fan:
41,000 fans x \( \frac{5}{6} \) = \( \frac{205000}{6} \) = 34,167 fans.
Which of these numbers is a factor of 64?
| 26 | |
| 54 | |
| 64 | |
| 41 |
The factors of a number are all positive integers that divide evenly into the number. The factors of 64 are 1, 2, 4, 8, 16, 32, 64.
Which of the following is a mixed number?
\({a \over 5} \) |
|
\(1 {2 \over 5} \) |
|
\({5 \over 7} \) |
|
\({7 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
What is \( 6 \)\( \sqrt{80} \) - \( 7 \)\( \sqrt{5} \)
| 42\( \sqrt{80} \) | |
| 17\( \sqrt{5} \) | |
| -1\( \sqrt{9} \) | |
| 42\( \sqrt{16} \) |
To subtract these radicals together their radicands must be the same:
6\( \sqrt{80} \) - 7\( \sqrt{5} \)
6\( \sqrt{16 \times 5} \) - 7\( \sqrt{5} \)
6\( \sqrt{4^2 \times 5} \) - 7\( \sqrt{5} \)
(6)(4)\( \sqrt{5} \) - 7\( \sqrt{5} \)
24\( \sqrt{5} \) - 7\( \sqrt{5} \)
Now that the radicands are identical, you can subtract them:
24\( \sqrt{5} \) - 7\( \sqrt{5} \)What is \( \frac{4}{4} \) + \( \frac{4}{8} \)?
| \( \frac{6}{8} \) | |
| 1 \( \frac{6}{8} \) | |
| 1\(\frac{1}{2}\) | |
| 2 \( \frac{5}{8} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80]. The first few multiples they share are [8, 16, 24, 32, 40] making 8 the smallest multiple 4 and 8 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{4 x 2}{4 x 2} \) + \( \frac{4 x 1}{8 x 1} \)
\( \frac{8}{8} \) + \( \frac{4}{8} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{8 + 4}{8} \) = \( \frac{12}{8} \) = 1\(\frac{1}{2}\)