If the tiger has consumed 90 pounds of food in 9 days that's \( \frac{90}{9} \) = 10 pounds of food per day. The tiger needs to consume 130 - 90 = 40 more pounds of food to reach 130 pounds total. At 10 pounds of food per day that's \( \frac{40}{10} \) = 4 more days.

40% of the water consumption is industrial use and 28% is personal use so (40% - 28%) = 12% more water is used for industrial purposes. 5,000 gallons are consumed daily so industry consumes \( \frac{12}{100} \) x 5,000 gallons = 600 gallons.

A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

Solving for distance:

distance = \( \text{speed} \times \text{time} \)
distance = \( 75mph \times 8h \)
600 miles

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

4 + (4 + 4) ÷ 5 x 2 - 4²
P: 4 + (8) ÷ 5 x 2 - 4²
E: 4 + 8 ÷ 5 x 2 - 16
MD: 4 + \( \frac{8}{5} \) x 2 - 16
MD: 4 + \( \frac{16}{5} \) - 16
AS: \( \frac{20}{5} \) + \( \frac{16}{5} \) - 16
AS: \( \frac{36}{5} \) - 16
AS: \( \frac{36 - 80}{5} \)
\( \frac{-44}{5} \)
-8\(\frac{4}{5}\)