| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.39 |
| Score | 0% | 68% |
Solve for \( \frac{3!}{6!} \)
| \( \frac{1}{504} \) | |
| 210 | |
| \( \frac{1}{120} \) | |
| 840 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{3!}{6!} \)
\( \frac{3 \times 2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6 \times 5 \times 4} \)
\( \frac{1}{120} \)
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 20% off." If Alex buys two shirts, each with a regular price of $42, how much will he pay for both shirts?
| $75.60 | |
| $60.90 | |
| $33.60 | |
| $50.40 |
By buying two shirts, Alex will save $42 x \( \frac{20}{100} \) = \( \frac{$42 x 20}{100} \) = \( \frac{$840}{100} \) = $8.40 on the second shirt.
So, his total cost will be
$42.00 + ($42.00 - $8.40)
$42.00 + $33.60
$75.60
What is the least common multiple of 4 and 6?
| 12 | |
| 14 | |
| 9 | |
| 21 |
The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60]. The first few multiples they share are [12, 24, 36, 48, 60] making 12 the smallest multiple 4 and 6 have in common.
a(b + c) = ab + ac defines which of the following?
distributive property for division |
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distributive property for multiplication |
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commutative property for division |
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commutative property for multiplication |
The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.
What is the next number in this sequence: 1, 4, 10, 19, 31, __________ ?
| 46 | |
| 43 | |
| 48 | |
| 47 |
The equation for this sequence is:
an = an-1 + 3(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 3(6 - 1)
a6 = 31 + 3(5)
a6 = 46