ASVAB Arithmetic Reasoning Practice Test 90025 Results

Your Results Global Average
Questions 5 5
Correct 0 3.04
Score 0% 61%

Review

1

Solve 3 + (3 + 2) ÷ 3 x 5 - 22

53% Answer Correctly
7\(\frac{1}{3}\)
1\(\frac{2}{3}\)
\(\frac{6}{7}\)
4

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

3 + (3 + 2) ÷ 3 x 5 - 22
P: 3 + (5) ÷ 3 x 5 - 22
E: 3 + 5 ÷ 3 x 5 - 4
MD: 3 + \( \frac{5}{3} \) x 5 - 4
MD: 3 + \( \frac{25}{3} \) - 4
AS: \( \frac{9}{3} \) + \( \frac{25}{3} \) - 4
AS: \( \frac{34}{3} \) - 4
AS: \( \frac{34 - 12}{3} \)
\( \frac{22}{3} \)
7\(\frac{1}{3}\)


2

What is 4a6 - 6a6?

71% Answer Correctly
-2a-6
-2a6
10a6
10a12

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

4a6 - 6a6
(4 - 6)a6
-2a6


3

What is \( 2 \)\( \sqrt{8} \) + \( 5 \)\( \sqrt{2} \)

35% Answer Correctly
7\( \sqrt{2} \)
10\( \sqrt{2} \)
10\( \sqrt{4} \)
9\( \sqrt{2} \)

Solution

To add these radicals together their radicands must be the same:

2\( \sqrt{8} \) + 5\( \sqrt{2} \)
2\( \sqrt{4 \times 2} \) + 5\( \sqrt{2} \)
2\( \sqrt{2^2 \times 2} \) + 5\( \sqrt{2} \)
(2)(2)\( \sqrt{2} \) + 5\( \sqrt{2} \)
4\( \sqrt{2} \) + 5\( \sqrt{2} \)

Now that the radicands are identical, you can add them together:

4\( \sqrt{2} \) + 5\( \sqrt{2} \)
(4 + 5)\( \sqrt{2} \)
9\( \sqrt{2} \)


4

What is \( \frac{3}{9} \) x \( \frac{3}{6} \)?

72% Answer Correctly
\(\frac{8}{35}\)
\(\frac{1}{6}\)
\(\frac{2}{63}\)
1\(\frac{1}{2}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{3}{9} \) x \( \frac{3}{6} \) = \( \frac{3 x 3}{9 x 6} \) = \( \frac{9}{54} \) = \(\frac{1}{6}\)


5

Which of the following is an improper fraction?

70% Answer Correctly

\({7 \over 5} \)

\(1 {2 \over 5} \)

\({2 \over 5} \)

\({a \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.