ASVAB Arithmetic Reasoning Practice Test 905677 Results

Your Results Global Average
Questions 5 5
Correct 0 3.43
Score 0% 69%

Review

1

What is (z4)3?

80% Answer Correctly
z7
z
4z3
z12

Solution

To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

(z4)3
z(4 * 3)
z12


2

Convert b-3 to remove the negative exponent.

68% Answer Correctly
\( \frac{-3}{-b} \)
\( \frac{-3}{b} \)
\( \frac{1}{b^3} \)
\( \frac{-1}{-3b^{3}} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.


3

Which of the following is a mixed number?

83% Answer Correctly

\({5 \over 7} \)

\({7 \over 5} \)

\(1 {2 \over 5} \)

\({a \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


4

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

56% Answer Correctly

commutative property for multiplication

commutative property for division

distributive property for multiplication

distributive property for division


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).


5

If all of a roofing company's 20 workers are required to staff 5 roofing crews, how many workers need to be added during the busy season in order to send 10 complete crews out on jobs?

55% Answer Correctly
4
18
9
20

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 20 workers at the company now and that's enough to staff 5 crews so there are \( \frac{20}{5} \) = 4 workers on a crew. 10 crews are needed for the busy season which, at 4 workers per crew, means that the roofing company will need 10 x 4 = 40 total workers to staff the crews during the busy season. The company already employs 20 workers so they need to add 40 - 20 = 20 new staff for the busy season.