ASVAB Arithmetic Reasoning Practice Test 906135 Results

Your Results Global Average
Questions 5 5
Correct 0 3.43
Score 0% 69%

Review

1

What is the next number in this sequence: 1, 3, 7, 13, 21, __________ ?

69% Answer Correctly
26
27
31
36

Solution

The equation for this sequence is:

an = an-1 + 2(n - 1)

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 2(6 - 1)
a6 = 21 + 2(5)
a6 = 31


2

What is \( \frac{20\sqrt{40}}{4\sqrt{8}} \)?

71% Answer Correctly
5 \( \sqrt{5} \)
\(\frac{1}{5}\) \( \sqrt{5} \)
\(\frac{1}{5}\) \( \sqrt{\frac{1}{5}} \)
5 \( \sqrt{\frac{1}{5}} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{20\sqrt{40}}{4\sqrt{8}} \)
\( \frac{20}{4} \) \( \sqrt{\frac{40}{8}} \)
5 \( \sqrt{5} \)


3

If \( \left|c - 7\right| \) + 2 = -7, which of these is a possible value for c?

62% Answer Correctly
-2
-8
4
3

Solution

First, solve for \( \left|c - 7\right| \):

\( \left|c - 7\right| \) + 2 = -7
\( \left|c - 7\right| \) = -7 - 2
\( \left|c - 7\right| \) = -9

The value inside the absolute value brackets can be either positive or negative so (c - 7) must equal - 9 or --9 for \( \left|c - 7\right| \) to equal -9:

c - 7 = -9
c = -9 + 7
c = -2
c - 7 = 9
c = 9 + 7
c = 16

So, c = 16 or c = -2.


4

What is the least common multiple of 2 and 10?

72% Answer Correctly
14
13
2
10

Solution

The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [10, 20, 30, 40, 50] making 10 the smallest multiple 2 and 10 have in common.


5

Which of the following is an improper fraction?

70% Answer Correctly

\({a \over 5} \)

\({7 \over 5} \)

\(1 {2 \over 5} \)

\({2 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.