To add these radicals together their radicands must be the same:

3\( \sqrt{28} \) + 7\( \sqrt{7} \)
3\( \sqrt{4 \times 7} \) + 7\( \sqrt{7} \)
3\( \sqrt{2^2 \times 7} \) + 7\( \sqrt{7} \)
(3)(2)\( \sqrt{7} \) + 7\( \sqrt{7} \)
6\( \sqrt{7} \) + 7\( \sqrt{7} \)

Now that the radicands are identical, you can add them together:

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 16 workers at the company now and that's enough to staff 4 crews so there are \( \frac{16}{4} \) = 4 workers on a crew. 8 crews are needed for the busy season which, at 4 workers per crew, means that the roofing company will need 8 x 4 = 32 total workers to staff the crews during the busy season. The company already employs 16 workers so they need to add 32 - 16 = 16 new staff for the busy season.

You have 4 out of the total of 50 raffle tickets sold so you have a (\( \frac{4}{50} \)) x 100 = \( \frac{4 \times 100}{50} \) = \( \frac{400}{50} \) = 9% chance to win the raffle.

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

3 + (2 + 4) ÷ 3 x 5 - 4²
P: 3 + (6) ÷ 3 x 5 - 4²
E: 3 + 6 ÷ 3 x 5 - 16
MD: 3 + \( \frac{6}{3} \) x 5 - 16
MD: 3 + \( \frac{30}{3} \) - 16
AS: \( \frac{9}{3} \) + \( \frac{30}{3} \) - 16
AS: \( \frac{39}{3} \) - 16
AS: \( \frac{39 - 48}{3} \)
\( \frac{-9}{3} \)
-3

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).