| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.89 |
| Score | 0% | 58% |
What is \( 7 \)\( \sqrt{12} \) + \( 3 \)\( \sqrt{3} \)
| 10\( \sqrt{12} \) | |
| 21\( \sqrt{4} \) | |
| 21\( \sqrt{3} \) | |
| 17\( \sqrt{3} \) |
To add these radicals together their radicands must be the same:
7\( \sqrt{12} \) + 3\( \sqrt{3} \)
7\( \sqrt{4 \times 3} \) + 3\( \sqrt{3} \)
7\( \sqrt{2^2 \times 3} \) + 3\( \sqrt{3} \)
(7)(2)\( \sqrt{3} \) + 3\( \sqrt{3} \)
14\( \sqrt{3} \) + 3\( \sqrt{3} \)
Now that the radicands are identical, you can add them together:
14\( \sqrt{3} \) + 3\( \sqrt{3} \)What is the greatest common factor of 60 and 52?
| 16 | |
| 4 | |
| 26 | |
| 2 |
The factors of 60 are [1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60] and the factors of 52 are [1, 2, 4, 13, 26, 52]. They share 3 factors [1, 2, 4] making 4 the greatest factor 60 and 52 have in common.
A circular logo is enlarged to fit the lid of a jar. The new diameter is 70% larger than the original. By what percentage has the area of the logo increased?
| 22\(\frac{1}{2}\)% | |
| 27\(\frac{1}{2}\)% | |
| 15% | |
| 35% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 70% the radius (and, consequently, the total area) increases by \( \frac{70\text{%}}{2} \) = 35%
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 50% off." If Damon buys two shirts, each with a regular price of $36, how much will he pay for both shirts?
| $54.00 | |
| $48.60 | |
| $18.00 | |
| $41.40 |
By buying two shirts, Damon will save $36 x \( \frac{50}{100} \) = \( \frac{$36 x 50}{100} \) = \( \frac{$1800}{100} \) = $18.00 on the second shirt.
So, his total cost will be
$36.00 + ($36.00 - $18.00)
$36.00 + $18.00
$54.00
Solve for \( \frac{2!}{3!} \)
| 504 | |
| 9 | |
| \( \frac{1}{56} \) | |
| \( \frac{1}{3} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{2!}{3!} \)
\( \frac{2 \times 1}{3 \times 2 \times 1} \)
\( \frac{1}{3} \)
\( \frac{1}{3} \)