ASVAB Arithmetic Reasoning Practice Test 91 Results

Your Results Global Average
Questions 5 5
Correct 0 3.05
Score 0% 61%

Review

1

A circular logo is enlarged to fit the lid of a jar. The new diameter is 70% larger than the original. By what percentage has the area of the logo increased?

50% Answer Correctly
27\(\frac{1}{2}\)%
22\(\frac{1}{2}\)%
17\(\frac{1}{2}\)%
35%

Solution

The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 70% the radius (and, consequently, the total area) increases by \( \frac{70\text{%}}{2} \) = 35%


2

52% Answer Correctly
1
4.8
0.5
0.8

Solution


1


3

The __________ is the greatest factor that divides two integers.

67% Answer Correctly

greatest common factor

absolute value

least common multiple

greatest common multiple


Solution

The greatest common factor (GCF) is the greatest factor that divides two integers.


4

What is \( \frac{5}{4} \) + \( \frac{8}{12} \)?

60% Answer Correctly
2 \( \frac{9}{12} \)
2 \( \frac{5}{12} \)
1\(\frac{11}{12}\)
2 \( \frac{1}{8} \)

Solution

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 12 are [12, 24, 36, 48, 60, 72, 84, 96]. The first few multiples they share are [12, 24, 36, 48, 60] making 12 the smallest multiple 4 and 12 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{5 x 3}{4 x 3} \) + \( \frac{8 x 1}{12 x 1} \)

\( \frac{15}{12} \) + \( \frac{8}{12} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{15 + 8}{12} \) = \( \frac{23}{12} \) = 1\(\frac{11}{12}\)


5

a(b + c) = ab + ac defines which of the following?

74% Answer Correctly

distributive property for division

commutative property for division

commutative property for multiplication

distributive property for multiplication


Solution

The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.