| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.42 |
| Score | 0% | 68% |
Solve 3 + (4 + 3) ÷ 2 x 4 - 42
| \(\frac{7}{9}\) | |
| 1 | |
| \(\frac{3}{5}\) | |
| \(\frac{5}{7}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
3 + (4 + 3) ÷ 2 x 4 - 42
P: 3 + (7) ÷ 2 x 4 - 42
E: 3 + 7 ÷ 2 x 4 - 16
MD: 3 + \( \frac{7}{2} \) x 4 - 16
MD: 3 + \( \frac{28}{2} \) - 16
AS: \( \frac{6}{2} \) + \( \frac{28}{2} \) - 16
AS: \( \frac{34}{2} \) - 16
AS: \( \frac{34 - 32}{2} \)
\( \frac{2}{2} \)
1
What is the distance in miles of a trip that takes 9 hours at an average speed of 50 miles per hour?
| 110 miles | |
| 360 miles | |
| 450 miles | |
| 75 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 50mph \times 9h \)
450 miles
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
commutative property for division |
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commutative property for multiplication |
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distributive property for multiplication |
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distributive property for division |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
How many 14-passenger vans will it take to drive all 99 members of the football team to an away game?
| 10 vans | |
| 7 vans | |
| 5 vans | |
| 8 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{99}{14} \) = 7\(\frac{1}{14}\)
So, it will take 7 full vans and one partially full van to transport the entire team making a total of 8 vans.
Convert c-3 to remove the negative exponent.
| \( \frac{-3}{-c} \) | |
| \( \frac{-1}{-3c^{3}} \) | |
| \( \frac{1}{c^{-3}} \) | |
| \( \frac{1}{c^3} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.