| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.95 |
| Score | 0% | 59% |
What is \( 6 \)\( \sqrt{28} \) + \( 3 \)\( \sqrt{7} \)
| 9\( \sqrt{7} \) | |
| 18\( \sqrt{4} \) | |
| 18\( \sqrt{7} \) | |
| 15\( \sqrt{7} \) |
To add these radicals together their radicands must be the same:
6\( \sqrt{28} \) + 3\( \sqrt{7} \)
6\( \sqrt{4 \times 7} \) + 3\( \sqrt{7} \)
6\( \sqrt{2^2 \times 7} \) + 3\( \sqrt{7} \)
(6)(2)\( \sqrt{7} \) + 3\( \sqrt{7} \)
12\( \sqrt{7} \) + 3\( \sqrt{7} \)
Now that the radicands are identical, you can add them together:
12\( \sqrt{7} \) + 3\( \sqrt{7} \)A tiger in a zoo has consumed 64 pounds of food in 8 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 112 pounds?
| 6 | |
| 8 | |
| 7 | |
| 12 |
If the tiger has consumed 64 pounds of food in 8 days that's \( \frac{64}{8} \) = 8 pounds of food per day. The tiger needs to consume 112 - 64 = 48 more pounds of food to reach 112 pounds total. At 8 pounds of food per day that's \( \frac{48}{8} \) = 6 more days.
Which of the following is an improper fraction?
\(1 {2 \over 5} \) |
|
\({7 \over 5} \) |
|
\({a \over 5} \) |
|
\({2 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
Monty loaned Damon $1,000 at an annual interest rate of 6%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $27 | |
| $72 | |
| $60 | |
| $13 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,000
i = 0.06 x $1,000
i = $60
The total water usage for a city is 10,000 gallons each day. Of that total, 19% is for personal use and 29% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 1,100 | |
| 8,400 | |
| 1,600 | |
| 1,000 |
29% of the water consumption is industrial use and 19% is personal use so (29% - 19%) = 10% more water is used for industrial purposes. 10,000 gallons are consumed daily so industry consumes \( \frac{10}{100} \) x 10,000 gallons = 1,000 gallons.