The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.

A number in scientific notation has the format 0.000 x 10^exponent. To convert to scientific notation, move the decimal point to the right or the left until the number is a decimal between 1 and 10. The exponent of the 10 is the number of places you moved the decimal point and is positive if you moved the decimal point to the left and negative if you moved it to the right:

0.0001162 in scientific notation is 1.162 x 10^-4

To subtract these radicals together their radicands must be the same:

2\( \sqrt{18} \) - 6\( \sqrt{2} \)
2\( \sqrt{9 \times 2} \) - 6\( \sqrt{2} \)
2\( \sqrt{3^2 \times 2} \) - 6\( \sqrt{2} \)
(2)(3)\( \sqrt{2} \) - 6\( \sqrt{2} \)
6\( \sqrt{2} \) - 6\( \sqrt{2} \)

Now that the radicands are identical, you can subtract them:

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{81}{36}} \)
\( \frac{\sqrt{81}}{\sqrt{36}} \)
\( \frac{\sqrt{9^2}}{\sqrt{6^2}} \)
\( \frac{9}{6} \)
1\(\frac{1}{2}\)