The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).

There are 2 2-passenger taxis available so that's 2 x 2 = 4 total seats. There are 5 people needing transportation leaving 5 - 4 = 1 who will have to find other transportation.

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{4}{9} \) x \( \frac{3}{7} \) = \( \frac{4 x 3}{9 x 7} \) = \( \frac{12}{63} \) = \(\frac{4}{21}\)

If the tiger has consumed 55 pounds of food in 11 days that's \( \frac{55}{11} \) = 5 pounds of food per day. The tiger needs to consume 75 - 55 = 20 more pounds of food to reach 75 pounds total. At 5 pounds of food per day that's \( \frac{20}{5} \) = 4 more days.

To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 200 meters to kilometers, divide the distance by 1000 to get 0.2km then add the remaining distances:

total distance = swim + bike + run
total distance = 0.2km + 40.5km + 3.0km
total distance = 43.7km