| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.52 |
| Score | 0% | 70% |
Convert b-2 to remove the negative exponent.
| \( \frac{-1}{-2b} \) | |
| \( \frac{2}{b} \) | |
| \( \frac{1}{b^2} \) | |
| \( \frac{-2}{-b} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.
Monty loaned Latoya $400 at an annual interest rate of 1%. If no payments are made, what is the total amount owed at the end of the first year?
| $404 | |
| $412 | |
| $432 | |
| $428 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $400
i = 0.01 x $400
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $400 + $4What is the next number in this sequence: 1, 6, 11, 16, 21, __________ ?
| 19 | |
| 26 | |
| 27 | |
| 32 |
The equation for this sequence is:
an = an-1 + 5
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 5
a6 = 21 + 5
a6 = 26
The __________ is the greatest factor that divides two integers.
absolute value |
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greatest common multiple |
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greatest common factor |
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least common multiple |
The greatest common factor (GCF) is the greatest factor that divides two integers.
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
distributive property for division |
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commutative property for multiplication |
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commutative property for division |
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distributive property for multiplication |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).