| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.34 |
| Score | 0% | 67% |
The total water usage for a city is 40,000 gallons each day. Of that total, 24% is for personal use and 46% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 2,500 | |
| 2,800 | |
| 8,800 | |
| 11,000 |
46% of the water consumption is industrial use and 24% is personal use so (46% - 24%) = 22% more water is used for industrial purposes. 40,000 gallons are consumed daily so industry consumes \( \frac{22}{100} \) x 40,000 gallons = 8,800 gallons.
4! = ?
3 x 2 x 1 |
|
4 x 3 x 2 x 1 |
|
4 x 3 |
|
5 x 4 x 3 x 2 x 1 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
A bread recipe calls for 1\(\frac{7}{8}\) cups of flour. If you only have 1\(\frac{1}{2}\) cups, how much more flour is needed?
| 2\(\frac{3}{4}\) cups | |
| \(\frac{5}{8}\) cups | |
| \(\frac{3}{8}\) cups | |
| 2\(\frac{7}{8}\) cups |
The amount of flour you need is (1\(\frac{7}{8}\) - 1\(\frac{1}{2}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{15}{8} \) - \( \frac{12}{8} \)) cups
\( \frac{3}{8} \) cups
\(\frac{3}{8}\) cups
How many 10-passenger vans will it take to drive all 39 members of the football team to an away game?
| 9 vans | |
| 4 vans | |
| 8 vans | |
| 6 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{39}{10} \) = 3\(\frac{9}{10}\)
So, it will take 3 full vans and one partially full van to transport the entire team making a total of 4 vans.
If a rectangle is twice as long as it is wide and has a perimeter of 30 meters, what is the area of the rectangle?
| 50 m2 | |
| 32 m2 | |
| 2 m2 | |
| 128 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 30 meters so the equation becomes: 2w + 2h = 30.
Putting these two equations together and solving for width (w):
2w + 2h = 30
w + h = \( \frac{30}{2} \)
w + h = 15
w = 15 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 15 - 2w
3w = 15
w = \( \frac{15}{3} \)
w = 5
Since h = 2w that makes h = (2 x 5) = 10 and the area = h x w = 5 x 10 = 50 m2