ASVAB Arithmetic Reasoning Practice Test 923164 Results

Your Results Global Average
Questions 5 5
Correct 0 3.07
Score 0% 61%

Review

1

What is \( \frac{9}{5} \) + \( \frac{4}{7} \)?

60% Answer Correctly
2\(\frac{13}{35}\)
1 \( \frac{9}{35} \)
2 \( \frac{5}{12} \)
1 \( \frac{2}{6} \)

Solution

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50] and the first few multiples of 7 are [7, 14, 21, 28, 35, 42, 49, 56, 63, 70]. The first few multiples they share are [35, 70] making 35 the smallest multiple 5 and 7 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{9 x 7}{5 x 7} \) + \( \frac{4 x 5}{7 x 5} \)

\( \frac{63}{35} \) + \( \frac{20}{35} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{63 + 20}{35} \) = \( \frac{83}{35} \) = 2\(\frac{13}{35}\)


2

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

56% Answer Correctly

commutative property for division

distributive property for division

distributive property for multiplication

commutative property for multiplication


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).


3

Which of the following is not a prime number?

65% Answer Correctly

5

2

9

7


Solution

A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.


4

Solve for \( \frac{3!}{5!} \)

67% Answer Correctly
5
\( \frac{1}{504} \)
\( \frac{1}{1680} \)
\( \frac{1}{20} \)

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{3!}{5!} \)
\( \frac{3 \times 2 \times 1}{5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{5 \times 4} \)
\( \frac{1}{20} \)


5

If there were a total of 300 raffle tickets sold and you bought 15 tickets, what's the probability that you'll win the raffle?

60% Answer Correctly
5%
12%
18%
11%

Solution

You have 15 out of the total of 300 raffle tickets sold so you have a (\( \frac{15}{300} \)) x 100 = \( \frac{15 \times 100}{300} \) = \( \frac{1500}{300} \) = 5% chance to win the raffle.