ASVAB Arithmetic Reasoning Practice Test 925426 Results

Your Results Global Average
Questions 5 5
Correct 0 3.30
Score 0% 66%

Review

1

What is the least common multiple of 3 and 5?

72% Answer Correctly
9
15
8
14

Solution

The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50]. The first few multiples they share are [15, 30, 45, 60, 75] making 15 the smallest multiple 3 and 5 have in common.


2

A triathlon course includes a 200m swim, a 50.2km bike ride, and a 7.7km run. What is the total length of the race course?

69% Answer Correctly
48.5km
58.1km
31.2km
33.4km

Solution

To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 200 meters to kilometers, divide the distance by 1000 to get 0.2km then add the remaining distances:

total distance = swim + bike + run
total distance = 0.2km + 50.2km + 7.7km
total distance = 58.1km


3

If a mayor is elected with 70% of the votes cast and 51% of a town's 42,000 voters cast a vote, how many votes did the mayor receive?

50% Answer Correctly
19,278
15,208
14,994
15,637

Solution

If 51% of the town's 42,000 voters cast ballots the number of votes cast is:

(\( \frac{51}{100} \)) x 42,000 = \( \frac{2,142,000}{100} \) = 21,420

The mayor got 70% of the votes cast which is:

(\( \frac{70}{100} \)) x 21,420 = \( \frac{1,499,400}{100} \) = 14,994 votes.


4

Solve for \( \frac{2!}{5!} \)

67% Answer Correctly
\( \frac{1}{60} \)
\( \frac{1}{7} \)
504
336

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{2!}{5!} \)
\( \frac{2 \times 1}{5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{5 \times 4 \times 3} \)
\( \frac{1}{60} \)


5

Ezra loaned Christine $300 at an annual interest rate of 9%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly
$309
$318
$327
$321

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $300
i = 0.09 x $300

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $300 + $27
total = $327