To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{16}{16}} \)
\( \frac{\sqrt{16}}{\sqrt{16}} \)
\( \frac{\sqrt{4^2}}{\sqrt{4^2}} \)
1

To subtract these radicals together their radicands must be the same:

5\( \sqrt{80} \) - 6\( \sqrt{5} \)
5\( \sqrt{16 \times 5} \) - 6\( \sqrt{5} \)
5\( \sqrt{4^2 \times 5} \) - 6\( \sqrt{5} \)
(5)(4)\( \sqrt{5} \) - 6\( \sqrt{5} \)
20\( \sqrt{5} \) - 6\( \sqrt{5} \)

Now that the radicands are identical, you can subtract them:

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{2!}{3!} \)
\( \frac{2 \times 1}{3 \times 2 \times 1} \)
\( \frac{1}{3} \)
\( \frac{1}{3} \)

guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 15 x \( \frac{60}{100} \) = \( \frac{60 x 15}{100} \) = \( \frac{900}{100} \) = 9 shots

The center makes 40% of his shots so he'll have to take:

shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)

to make as many shots as the guard. Plugging in values for the center gives us:

center shots taken = \( \frac{9}{\frac{40}{100}} \) = 9 x \( \frac{100}{40} \) = \( \frac{9 x 100}{40} \) = \( \frac{900}{40} \) = 23 shots

to make the same number of shots as the guard and thus score the same number of points.

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

3z⁷ - 7z⁷
(3 - 7)z⁷
-4z⁷