| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.27 |
| Score | 0% | 65% |
a(b + c) = ab + ac defines which of the following?
commutative property for division |
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distributive property for division |
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commutative property for multiplication |
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distributive property for multiplication |
The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.
Solve for \( \frac{5!}{6!} \)
| 6 | |
| \( \frac{1}{60480} \) | |
| \( \frac{1}{6} \) | |
| \( \frac{1}{30} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{5!}{6!} \)
\( \frac{5 \times 4 \times 3 \times 2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6} \)
\( \frac{1}{6} \)
Alex loaned Jennifer $200 at an annual interest rate of 8%. If no payments are made, what is the total amount owed at the end of the first year?
| $212 | |
| $202 | |
| $210 | |
| $216 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $200
i = 0.08 x $200
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $200 + $16A tiger in a zoo has consumed 80 pounds of food in 8 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 140 pounds?
| 5 | |
| 2 | |
| 11 | |
| 6 |
If the tiger has consumed 80 pounds of food in 8 days that's \( \frac{80}{8} \) = 10 pounds of food per day. The tiger needs to consume 140 - 80 = 60 more pounds of food to reach 140 pounds total. At 10 pounds of food per day that's \( \frac{60}{10} \) = 6 more days.
What is \( \frac{8}{2} \) + \( \frac{6}{6} \)?
| \( \frac{3}{6} \) | |
| 2 \( \frac{2}{6} \) | |
| 5 | |
| 1 \( \frac{8}{6} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60]. The first few multiples they share are [6, 12, 18, 24, 30] making 6 the smallest multiple 2 and 6 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{8 x 3}{2 x 3} \) + \( \frac{6 x 1}{6 x 1} \)
\( \frac{24}{6} \) + \( \frac{6}{6} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{24 + 6}{6} \) = \( \frac{30}{6} \) = 5